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jasenka [17]
3 years ago
13

A shipment of 288 reams of paper was delivered. Each of the 30 classrooms recieved an equal share of equipment paper. Any extra

reams of paper were stored. After the paper was distributed to the classrooms, how many reams of paper were stored?
Mathematics
1 answer:
Andrei [34K]3 years ago
8 0
288 divided by 30 equals 9 with a remainder of 18

= 9 R 18
<span>= 9 18/30</span>
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Solve the equation: (5y + 2)(y - 3) = -13(2 + y)
storchak [24]

Answer:

2i

Step-by-step explanation:

Distribute:

(5y + 2)(y - 3)

5y^2-15y+2y-6

Which can be simplified into 5y^2-13y-6

Now the equation now looks like this: 5y^2-13y-6=-13(2+y)

For -13(2+y) multiply -13 with 2+y

Which is -26-13y

5y^2-13y-6=-26-13y

Simplify:

5y^2+20

Which can be simplified into 5(y^2+4)

y^2+4=0

y^2=-4

y=2i

Hope this helps!

7 0
3 years ago
Please helpppp it has to do with P(A U B)
Katyanochek1 [597]
P(A)=0.5, P(B)=0.6, P(A\cup B)=0.8

We find the probability of intersection using the inclusion/exclusion principle:


P(A\cap B)=P(A)+P(B)-P(A\cup B)=0.3


By definition of conditional probability,


P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{0.3}{0.6}=0.5


For A and B to be independent, we must have


P(A\cap B)=P(A)\cdot P(B)

in which case we have 0.3=0.5\cdot0.6, which is true, so A and B are indeed independent.


Or, to establish independence another way, in terms of conditional probability, we must have

P(A\mid B)\cdot P(B)=P(A)\cdot P(B)\implies P(A\mid B)=P(A)


which is also true.
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B+10≤-1 What is the solution of the inequality
Mademuasel [1]
B is less than or equal to -11
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kompoz [17]

Answer:

6.4

Step-by-step explanation:

multiply

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3 years ago
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30 percent will be filled I am positive that is it
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3 years ago
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