Answer:
kuha ka bato pukpok mo sa ulo mo para malaman mo
Answer:
Step-by-step explanation:
~Kandy~
Hope this helped!
Brainliest please!
Ur answer would be B.. Hope it helps let me know if its right or not!
Step-by-step explanation:
ANOVA table Source SS df MS F
p-value Factor 1 12.00 1 12.000 1.20 .3153
Factor 2 8.00 2 4.000 0.40 .6870 Interaction 56.00 2 28.000 2.80 .1384
Error 60.00 6 10.000 Total 136.00 11
Since the p -value for Factor A is greater than 0.1, therefore Factor A is not significant. The p -value for Factor B is greater than 0.1, therefore Factor B is not significant. It should be noted that for P-value of both Factor and Factor B to be significant, each factor must not be greater than 0.1
Looking at the chart, we can see that with diet chow, the weight changed by -26, while with kitty diet, it changed by -13. Therefore, the Diet Chow was more effective
