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2 years ago

What is 2 and 5/6 divided by 6 and 4/5

1 answer:

3 0

Firstly I would revert these back to improper fractions:

So 17/6 ÷ 24/5

Then I would use keep, change, flip

So 17/6 * 5/24

Finally simplify

85/144

Final Answer: 85/144

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/<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-9%7D%7B15%7D%20%3D%5Cfrac%7B2x-9%7D%7B10%5C%5C%7D" id="TexFormula1" title="\frac{

motikmotik

Step-by-step explanation:

$\frac{x - 9}{15} = \frac{2x - 9}{10} \\$

$\frac{x - 9}{3} = \frac{2x - 9}{2} \\$

$2( x - 9) = 3(2x - 9) \\$

$2x - 18 = 6x - 27$

$27 - 18 = 6x - 2x$

$9 = 4x$

$x = \frac{9}{4} \\$

5 0

1 year ago

Which table corresponds to the equation y = −3x −2?

Yuri [45]

Answer:

Step-by-step explanation:

7 0

2 years ago

A survey shower that 82% of adults need correction for their eyesight. If 18 adults are randomly selected, find the probability

Ksju [112]

Answer: yes.

Step-by-step explanation:

18 people × .82 percent = 14.76

4 0

2 years ago

Secants L J and L M intersect and form an angle at point L. Solve for x.

german

Answer:

x = 14

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

$\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}$

Check:

$\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}$

It checks.

6 0

2 years ago

A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of th

AlladinOne [14]

$\bf \begin{array}{lllll}
round(x)&\boxed{1}&2&3&\boxed{4}\\\\
wrestlers[f(x)]&\boxed{64}&32&18&\boxed{9}
\end{array}
\\\\\\
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \qquad 
\begin{cases}
x_1=1\\
x_2=4
\end{cases}\implies \cfrac{f(4)-f(1)}{4-1}\implies \cfrac{9-64}{4-1}\implies \cfrac{-55}{3}$

55 over 3, or 55 wrestlers for every 3 rounds, but the wrestlers value is negative, thus 55 "less" wrestlers for every 3 rounds on average.

6 0

2 years ago

Read 2 more answers