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Talja [164]
3 years ago
7

Which is the simplified form of n to the -6th power times p to the 3 power?

Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0

Answer:

The simplified form of n to the -6th power times p to the 3 power is \frac{p^3}{n^6}.

Step-by-step explanation:

 Given problem: n to the -6th power times p to the 3 power

We have to write the simplified form  of given problem.

Consider the given expression n to the -6th power times p to the 3 power.

we can write the expression mathematically as

n to the -6th power can be written as n^{-6}

and p to the 3 power can be written as p^{3}

Combining both,   n to the -6th power times p to the 3 power.

written as n^{-6}\times p^3

Using property of exponent a^{-n}=(\frac{1}{a} )^n , we get,

n^{-6}\times p^3 as (\frac{1}{n} )^6\times p^3

Simplifying, we get,

\frac{p^3}{n^6}

Thus, the simplified form of n to the -6th power times p to the 3 power is \frac{p^3}{n^6}.

sergeinik [125]3 years ago
6 0
To make a negative exponent become positive we will put it under a 1.  So our n to the -6 power becomes \frac{1}{n^6}.  If we multiply that by p to the 3rd, we have \frac{1}{n^6}* \frac{p^3}{1} which simplifies to \frac{p^3}{n^6} and that's as simple as it can get.
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3 years ago
[(3 x 2) - 2 x 1.25]
kondor19780726 [428]

Answer:

3.5

Step-by-step explanation:

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5 0
4 years ago
Read 2 more answers
If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
elixir [45]

The vertex U' is located at (-4, -5)

<h3>How to determine the location of U'?</h3>

The vertices are given as:

U = (-4, 5)

V = (-6, 2)

The rule of transformation is given as:

Reflection across the x-axis

This is represented as:

(x, y) => (x, -y)

So, we have:

U' = (-4, -5)

Hence, the vertex U' is located at (-4, -5)

Read more about transformation at:

brainly.com/question/11707700

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<u>Complete question</u>

Quadrilateral UVWX is reflected over the x-axis to form quadrilateral U′V′W′X′. If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at

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