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3 years ago

A form of reasoning called_ is the process of forming general ideas and

Mathematics

2 answers:

hodyreva [135]3 years ago

7 0

Answer:

Inductive

Step-by-step explanation:

jarptica [38.1K]3 years ago

5 0

Answer:

The answer is inductive reasoning.

Step-by-step explanation:

A form of reasoning called Inductive reasoning is the process of forming general ideas and rules based on your experiences and observations.

Inductive reasoning takes in account, multiple premises that are believed to be true and combine all these to deduce a specific conclusion.

This is used in usually prediction and forecasting applications.

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ludmilkaskok [199]

18/13 or in simplified form, 1 and 5/13.

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3 years ago

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What basic trigonometric identity would you use to verify that (sin2x + cos2x)/cosx=secx

Oksana_A [137]

Answer:

Step-by-step explanation:

sin(2x) = 2 sin(x) cos(x) cos(2x) = cos2(x) – sin2(x) = 1 – 2 sin2(x) = 2 cos2(x) – 1. Now I am not sure if this is right but I remember another similar formula. Here is the correct formula cot x = cos x / sin x

2 ) ( sin² x + cos² x ) / cos x = sec x

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3 years ago

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Solve the inequality.

mr Goodwill [35]

Answer:

which inequality? where the question ?

Step-by-step explanation:

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3 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

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3 years ago

Help asap pleasee, I'LL GIVE BRAINLIEST FOR THIS QUESTION

pochemuha

Answer:

C is the answer

Step-by-step explanation:

2π/2 = π

8 0

2 years ago

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