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3 years ago

Evaluate 1/2m - 2/3n when m = 3 and n = 8.

Mathematics

1 answer:

Anika [276]3 years ago

7 0

Answer:

1/2(3)-2/3(8)

3/2-9/3

3-9

2.3

9-32

-23

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A car travels 81 miles in 3 hours. If it continues traveling at the same rate, how many miles would it travel in 5 hours?

wel

The car would travel 135 miles bc you multiply 81×5 and get 405 ,then divide that answer by 3

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2 years ago

Janice is training for a 5K. She predicted she would spend 90 minutes running this week. She actually ran for a total of 120 min

Levart [38]

I agree with the other person that this is 25% error

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2 years ago

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Divide the number 720 into the following Ratios 2:1:3 5:4

solmaris [256]

Answer:

Ratio 1 = a(240

=b)120

=c)360

Ratio 2=a)400

=b)320

Step-by-step explanation:

On both of the ratios you first add them then divide one by one like this for example 2+1+3= 6

then 2/6 ÷720 = 120 ×2 =240 then you do this to the other numbers as well.

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2 years ago

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Find the length of an arc made by a 180-degree central angle in a circle with a 10ft radius

mixas84 [53]

Answer:

the length of an arc = 10π ft.

Step-by-step explanation:

The length of an arc with angle Θ and radius r will be equal r * Θ

note the angle must be in radian

Given: Θ = 180° = π and radius = r = 10 ft.

So, the length of the arc = π * 10 = 10π ft.

8 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

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2 years ago