2 years ago

What is the value of 4

Mathematics

1 answer:

Stells [14]2 years ago

8 0

The value of 4 is in the ones place

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What is y=4x^2-9x+1 in vertex form

Anna11 [10]

Answer:

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

Step-by-step explanation:

$y = 4x^2 - 9x + 1$

You need to complete the square on the right side.

$y = (4x^2 - 9x) + 1$

$y = 4(x^2 - \dfrac{9}{4}x) + 1$

$y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}$

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$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

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2 years ago

Find the value of (-1/2)³

Evgen [1.6K]

Answer:

-1/8

Step-by-step explanation:

(-1/2) ^3

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-1/8

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Step-by-step explanation:

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2+x=7 x=5 eso es todo

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7-z=2

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3 years ago