If we call the leg of the small triangle y, and the leg perpendicular to x z, we can apply Pythagoras 3 times:
(1) 4 + y^2 = x^2
(2) x^2 + z^2 = 196 => z^2 = 196-x^2
(3) y^2 + 144 = z^2 => y^2 = z^2 - 144
Now fill in (3) in (1):
4 + z^2 - 144 = x^2
and then (2) in (1):
196-x^2-140 = x^2 => 2x^2 = 56 => x = √28 = 2√7
Answer C!
Answer:7600
Step-by-step explanation:
B. Cannot have 2 y points on the same x point. Confirm with the vertical line test.
Answer:
see below
Step-by-step explanation:
(2x + i)(2x – i)
FOIL
first 2x*2x =4x^2
outer -i * 2x = 2x i
inner i * 2x = 2x i
last i * -i = -i^2 and i^2 = -1 so - (i^2 ) = - (-1) = 1
Add together
4x^2 + 2xi -2x i +1
Combine like terms
4x^2 +1
