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Morgarella [4.7K]
3 years ago
14

4x + 20 degrees 40 degree angle

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

90 degree angle witch is Obtuse angle

welcomeeeee Yasssssssss

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There were some people on a train. 19 people got off the train at the first stop. 17 people get on the train. Now there is 63 pe
maria [59]

Answer:

65 people.

Step-by-step explanation:

We have to work backwards.

We end with 63 people, and at the stop we lost 19 people and gained 17.

x - 19 + 17 = 63\\; if x = # people at the beginning

x - 19 + 17 = 63\\x - 2 = 63\\x = 65

There were 65 people on the train to begin with.

6 0
3 years ago
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Find the distance between -2/3 and 4/3 on a number line
finlep [7]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,159 was collected on the sale of 1,339 ticket
ivolga24 [154]

Answer:

  • 455 adult tickets
  • 884 student tickets

Step-by-step explanation:

Let "a" represent the number of adult tickets sold. Then 1339-a is the number of student tickets sold. The revenue collected was ...

  5a + 1(1339-a) = 3159

  4a = 1820 . . . . . . subtract 1339, collect terms

  a = 455 . . . . . . . . divide by 4; adult tickets sold

  (1339-a) = 884 . . . . student tickets sold

455 adult tickets and 884 student tickets were sold.

5 0
3 years ago
It doesn't matter which of the two points on a line you choose to call (x1, y1) and which you choose to call (x2, y2) to calcula
frosja888 [35]
The correct answer is true ~ Apex 
3 0
3 years ago
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