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Morgarella [4.7K]
3 years ago
14

4x + 20 degrees 40 degree angle

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

90 degree angle witch is Obtuse angle

welcomeeeee Yasssssssss

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A tree in leilas backyard has been growing for 3 1/5 years. It is 3/4 meters tall how many meters per year?
IgorC [24]

Answer:

The tree grew 15/64 meters per year.                  

Step-by-step explanation:

Given

  • Length of a tree = 3/4 meters
  • Total time taken by the tree to grow 3/4 taller = 3 1/5 or 16/5 years

To determine

Per year growth of the tree in meters

Per year growth of the tree in meters can be determined by dividing the total length of a tree i.e. 3/4 meters by the total time taken by the tree to get 3/4 taller.

Per year growth of tree = Total Length  / Total time to grow

                                       = 3/4 ÷ 16/5

                                        = 3/4 × 5/16

                                        = [3×5] / [4×16]

                                        = 15/64 meters

Therefore, the tree grew 15/64 meters per year.                  

4 0
2 years ago
Please help, I'll mark brainliest.
GREYUIT [131]
I'm almost certain it's C :)
8 0
3 years ago
If g (x) = 3x²-4, then find g (-3)
Semenov [28]

Answer:

g(-3) = 23

Step-by-step explanation:

This question is telling us that x = -3. Knowing this, we can plug x into the equation and solve to find g(-3).

g(-3) = 3(-3)^{2} -4

g(-3) =3(9)-4                      Square -3 to get 9

g(-3) = 27-4                         Multiply 9 by 3 to get 27

g(-3) = 23                               Subtract 4 from 27 to get 23

Thus, g(-3) is equal to 23.

I hope this helps! Good luck!

6 0
2 years ago
How is this answer D?
kompoz [17]
It's a equilateral triangle with each side being equal to the radius.

So the area is \dfrac{8^2\sqrt 3}{4}=\dfrac{64\sqrt3}{4}=16\sqrt3
7 0
3 years ago
Two intelligent, honest students are sitting together at lunch one day when their math teacher hands them each a card. “your car
Lady bird [3.3K]
Answer: The loser's card shows 6.

Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
4     3
5     3
6     2
6     3
9     2
12  1
15  1
18  1

Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
6     2
6     3

Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.

2     6
3     6

Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
4 0
3 years ago
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