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andre [41]
3 years ago
14

Could you divide 14 shirts into two equal groups?why or why not

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0
Yes, there would be 7 shirts in each group. 14 ÷ 2 is 7, in case you need it.
Papessa [141]3 years ago
6 0
Yes, seven shirts a group
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Delvig [45]

Answer:

x=76

Step-by-step explanation:

The two marked angles are alternate angles, which means they're equal.

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I hope someone can help me here please don't answer nonsense!​
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2) By the inscribed angle theorem, arc RT measures twice 63 degrees, or 126 degrees.

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3 years ago
A is directly proportional to b. When a is 6, b is 72. Find b when a is 8. 3
adelina 88 [10]

Answer:

a)  <em>"K" is proportional Constant   K= 0.0833</em>

<em>b)     The value of b = 99.639</em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given   'a' is directly proportional to 'b'

                     a ∝ b

                <em>  a  =  k b ....(i)</em>

<em>where "K" is proportional Constant</em>

<u><em>Case(i)</em></u><em>:-</em>

<em>when a =6  and b=72</em>

<em>               a  =  k b     </em>

<em>          ⇒ 6 = k (72)</em>

<em>        ⇒  </em>K = \frac{6}{72} = \frac{1}{12} = 0.0833<em>      </em>

<u><em>Case(ii)</em></u><em>:-      </em>

<em> Given  a = 8.3  </em>

<em>           a  =  k b     </em>

<em>⇒   8.3 = 0.0833 ×b</em>

<em>⇒  </em>b = \frac{8.3}{0.0833} = 99.639<em></em>

<u><em>Final answer</em></u><em>:-</em>

a)<em>"K" is proportional Constant   K= 0.0833</em>

<em>b)     The value of b = 99.639</em>

<em></em>

<em></em>

<em></em>

<em></em>

6 0
2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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