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Roman55 [17]
3 years ago
10

A bag contains 3 red marbles, 7 blue marbles, and 2 green marbles. What is the probability of choosing a blue marble when one ma

rble is drawn?
Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0

Answer:

7/12

Step-by-step explanation:

To find the probability of drawing a blue marble you need to find how many marbles there are in total.

So you have to add 3 red marbles, 7 blue marbles, and 2 green marbles to get the total.

So 3 + 7 + 2 = 12

There are 12 marbles in total so now you have to find how many blue marbles there are.

There are 7 blue marbles out of 12 marbles.

Now you have to put this as a fraction to see if it can be simplified.

7/12 cant be simplified, so the probability of drawing a blue marble is 7/12.

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Answer:

The probability that you get zero questions correct is 0.4096

The probability that you get one questions correct is 0.4096

The probability that you get three questions correct is 0.0256

Step-by-step explanation:

These probability can be describe with a Binomial Distribution. These distribution can be used when we have n identical and independent situations in which there is a probability p or probability of success and a probability q or probability of fail. Additionally q is equal to 1 - p. The probability of x for a situation in which we can apply binomial distribution is:

P( x,n,p) = n Cx * p^{x } * q^ {n-x}

Where x is the variable that says the number of success in the n situations

And nCx is calculate as:

nC x = \frac{ n!}{ x! (n-x)! }

From the question we can identify that:

  • n is equal to 4 multiple choice question
  • p is 1/5 or 0.2, the probability of get one question correct
  • q is 4/5 or 0.8, the probability of get one question incorrect

Then the probability of get zero questions correct of 4 questions is:

P( 0, 4, 0.2) = 4 C0 * p^{0 } * q^ {4-0}= 0.4096

The probability of get one question correct of 4 questions is:

P( 1, 4, 0.2) = 4 C1 * p^{1 } * q^ {4-1}= 0.4096

The probability of get three questions correct of 4 questions is:

P( 3, 4, 0.2) = 4 C3 * p^{3 } * q^ {4-3}= 0.0256

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Step-by-step explanation:

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