Did you need the answer to the equation? Or did you need the term of the equation?
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
The time to complete 2 levels is (c) 60 minutes
<h3>How to determine the time to complete 2 levels?</h3>
The table of values is given as
Number of Levels Time (hours)
2 ?
3 1.5
Express the blank (?) with y
Number of Levels Time (hours)
2 y
3 1.5
The ordered pairs from the table are
(x, y) = (2, y) and (3, 15)
The table shows the proportional relationship
This means that the equation can be represented as
y = Y/X * x
Where
(x, y) = (2, y)
(X, Y) = (3, 1.5)
So, we have
y = 1.5/3 * 2
Evaluate the quotient
y = 0.5 * 2
This gives
y = 1 hour
Convert to minutes
y = 60 minutes
Hence, the time is 60 minutes
Read more about linear equation at
brainly.com/question/13738662
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Number: 1111
1111/1111=1
1*0= 0
Now put 0 in the tenths place
01
Hope this Helped :)