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Paul [167]
3 years ago
7

If f and g are two functions defined by f(x)=3x+5 and g(x)=x^2+1 find f^-1 (x)

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

y = 1/3(x-5)

Step-by-step explanation:

To find the inverse of a function switch the x and y and then solve for y.

x = 3y + 5

x-5 = 3y

(x-5)/3 = y

Or

y = 1/3(x-5)

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Is1/10 and 3/33 epuivalant
sveta [45]
3/33 can be reduced to 1/11 by dividing by 3 on the top and bottom.
1/11 is not equal to 1/10. Although they have the same numerator or number on top, 1, they don't have the same number in the bottom. 
So they are not equivalent.
Hope this helps. 
7 0
3 years ago
Read 2 more answers
Solve for r.<br><br> 27r = 783
Ksju [112]

Answer:29

Step-by-step explanation:

27r=783

   divide both sides by 27

 27r÷27=783÷27

         r=29

6 0
3 years ago
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the sum of two consecutive integers is three times their difference.what is the larger number.please help!​
Vesnalui [34]

9514 1404 393

Answer:

  2

Step-by-step explanation:

If n is the larger integer, n-1 is the smaller. The difference of consecutive integers is 1, so their sum is ...

  n +(n -1) = 3(1)

  2n = 4 . . . . . . . . . add 1

  n = 2 . . . . . . . . . . divide by 2

The larger integer is 2.

4 0
3 years ago
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Given that P(A)=0.5 and p(AUB)=0.6 find the P(B) if P(A/B) =0.4?
Yuki888 [10]
First we have to find p(AnB)
P(A/B)=p(AnB)/p(A)
P(AnB)=p(A) x p(A/B)
P(AnB)=0.5 x 0.4 = 0.2
Then to find p(B)
P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.5+p(B)-0.2
0.6=0.3+p(B)
P(B)=0.6-0.3=0.3

4 0
2 years ago
Use rounding to estimate the product
sdas [7]

Answer:

The estimate of the product is about 35 answer C

Step-by-step explanation:

- We use rounding to estimate the product of two fractions

- The mixed number has whole number and fraction

- To round the mixed number we look to the fraction

- If the numerator is half or greater than half the denominator, then we

  add the whole number by 1 and cancel the fraction

- If the numerator is less than half the denominator, then we keep the

  whole number as it and cancel the fraction

- Ex: If the mixed number is 2\frac{3}{4}, 3 is more than

 half 4 then we will add 2 by 1 and cancel the fraction part, the

 mixed number 2\frac{3}{4} after rounding is 3

- Ex: If the mixed number is 5\frac{1}{4}, 1 is less than

 half 4 then we will keep 5 as it and cancel the fraction part, the

 mixed number 5\frac{1}{4} after rounding is 5

* Lets solve the problem

∵ In the part 4\frac{3}{4} 3 is more than half 4

∴ The rounding value of 4\frac{3}{4} is 5

∵ In the part 7\frac{2}{17} 2 is less than half 17

∴ The rounding value of 7\frac{2}{17} is 7

∴ 4\frac{3}{4}*7\frac{2}{17}=5*7=35

* <em>The estimate of the product is about 35</em>

6 0
3 years ago
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