Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)
Answer:
187.9436
Step-by-step explanation:
Multiply
Ok so first we need to distribute so:
<span>=<span><span><span><span><span>(4)</span><span>(b)</span></span>+<span><span>(4)</span><span>(2)</span></span></span>+</span>−<span>3b
</span></span></span>=<span>4b+8+−3b
</span>So now that we've distrubuted that we are now going to Combine Like Terms:
<span>=<span><span><span>4b</span>+8</span>+<span>−<span>3b
</span></span></span></span><span>=<span><span>(<span><span>4b</span>+<span>−<span>3b</span></span></span>)</span>+<span>(8)
Finally your answer is:
</span></span></span><span>=<span>b+<span>8
I hope this helps you!</span></span></span>
