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3 years ago

Ralph runs at a constant rate of 3 miles per hour how long will it take ralph to run 15 miles

2 answers:

6 0

He runs 3 miles per hour and he wants to run 15 miles
15 divided by 3 which would equal 5
He would need 5 hours to run 15 miles

solmaris [256]3 years ago

4 0

It will take Ralph 5 hours to run 15 miles at a rate of 3/mph

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Suppose you carry out a significance test of h0: μ = 8 versus ha: μ > 8 based on sample size n = 25 and obtain t = 2. 15. Fin

OLEGan [10]

Using a t-distribution calculator and finding the p-value, the correct option regarding the conclusion is given by:

a) the p-value is 0.02. We reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.

<h3>What is the relation between the p-value and the conclusion?</h3>

It also involves the significance level, as follows.

If the p-value is less than the significance level, we reject the null hypothesis $h_0$ .

If it is more, we do not reject.

In this problem, a t-distribution calculator for a right-tailed with <em>t = 2.15 and 25 - 1 = 24 df</em> is used to find a p-value of 0.02.

It is less than 0.05, hence option a is correct.

More can be learned about p-values at brainly.com/question/26454209

5 0

2 years ago

A regular octagon has a radius of 6 ft and a side length of 4.6 ft. what is the approximate area of the octagon? 71 ft2 101 ft2

Zielflug [23.3K]

The answer is 101 ft^2

3 0

3 years ago

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You have a recipe that indicates to use 3 parts milk for every 2 parts sugar You use 12 cups of milk How much sugar do you need

Stells [14]

Proportion
3 parts milk. 12cups
2 parts sugar X

8 cups sugar

8 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

3 years ago

How I do 4 boxes that weighed total of 34 kilograms if each box had the same amount

Blizzard [7]

Each box would have exactly 8.5 kilograms each in them. Hope this helps mate =)

4 0

3 years ago

Read 2 more answers