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ki77a [65]
3 years ago
6

Solve for x:3/2x-2=-5

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0

The answer is X = -2

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Chords AB and CB intersect at E in circle O, as shown in the diagram below. Secant
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Step-by-step explanation:

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2 years ago
Where would you place root 8 on the Venn diagram? A) integers B) natural numbers C) rational numbers D) irrational numbers
tangare [24]

Answer:

Option (D)

Step-by-step explanation:

All rational and irrational numbers are real numbers.

{-2, -1, -1.8, 0, 1, 2.......}

Numbers written in the form of \frac{p}{q} are rational numbers. They are the part of irrational numbers.

{-2.5, -2, -1, 0, 1, 2.....}

Whole numbers with negative or positive notation are integers.

{-3, -2, -1, 0, 1, 2, 3, 4......}

Positive integers are the whole numbers (including zero).

{0, 1, 2, 3, 4, .......}

All whole numbers excluding zero are the natural numbers.

{1, 2, 3, 4,........}

Irrational numbers are the part of real numbers written in the form of \frac{p}{q}.

{\sqrt{2},\sqrt{5},\pi, \sqrt{10}}

Therefore, \sqrt{8} comes under Irrational numbers.

Option (D) is the answer.

7 0
3 years ago
A con is tossed n times. How many difference sequences of head and tails can you get?
ryzh [129]

Answer:

2^n

Step-by-step explanation:

So whenever you flip a coin, you can see it as 2 nodes branching off of each existing node. so for example when you flip a coin once you're going to have 2 sequences initially H and T, now when you flip a coin again for each of those 2 sequences 2 are going to branch off of that, making the total sequences 4, and the next flip 2 sequences are going to branch off each of the 4 sequences and so on. this can generally be described as: 2^n

I attached an image describing this a bit better but the bottom line is that for each 'end node'/sequence you're going to have 2 branch off of it, thus for each coin flip the number of sequences multiplies by 2

5 0
2 years ago
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jenyasd209 [6]

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11g + 19

Hope this helps

Step-by-step explanation:

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3 years ago
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Thomas lives more than 0.55 km and less than 0.75 km from his school.
S_A_V [24]

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C 0.60km

I hope this answer helps if you have any questions just ask

6 0
3 years ago
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