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Allushta [10]
3 years ago
14

5h+6y+4h+9y=3h+5y6h+9y

Mathematics
1 answer:
Leokris [45]3 years ago
3 0
H=6y/5y^(6) -6

hope this helps!!!!!!!!
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four students had the following amounts of money in their pockets:$3.14,$67,$2.45,and$1.14.how much money did they have total?br
Anvisha [2.4K]
The total amount they all have adds up to 73.73
8 0
4 years ago
Which equation represents a proportional relationship?
Verizon [17]

y = 3 x equation represents a proportional relationship.

Answer: Option B

<u>Step-by-step explanation:</u>

A proportional variation represents a relationship between two variables x and y. It can be expressed in the form y=k x. Here, the ‘k’, the proportionality constant is equal to the slope m and the line goes through the origin

case A) y=2\left(x+\frac{1}{3}\right)

A linear equation that not passes through the origin and so not proportional variation

case B) y= 3 x

Is a linear equation but passes through the origin and so proportional variation

case C) y = - 3x+2

A linear equation that not passes through the origin and so not proportional variation

case D)  \text { D) } y=\frac{1}{2 x}

An inverse variation equation but not passes through the origin and so not proportional variation.

From these, equation option B is the proportion equation because in these equations, there is no addition and subtraction of any constant number. That’s why both these equations become proportional equations.

5 0
3 years ago
Read 2 more answers
Can anyone help find x?
sergejj [24]

Answer:

x = 112°

Step-by-step explanation:

To find the value of x, you need to understand the properties of vertical and supplementary angles and know that the sum of angles inside a triangle is 180°.

6 0
3 years ago
4.2.32
aliina [53]

Answer:

Teo is 6 and Richard is 23

5 0
3 years ago
Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x) ​
Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

f(x)=x^4-3x^3+6x^2+2x-60

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

x-(1+3i)

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

x-(1-3i)

is a factor of given expression.

Thus, we can write:

(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}

Dividing f(x) by above expression:

\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6

To find the root, we equate it to zero:

x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0
4 years ago
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