Ask question

Ask question

All categories

Keith_Richards [23]

3 years ago

13

So..i can't do the limit..can you please help me...i am sure that a have to apply the test for divergence.

1 answer:

stich3 [128]3 years ago

7 0

Holy moleey what are you learning

You might be interested in

Consider the transformation T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v

irina1246 [14]

Answer:

Step-by-step explanation:

$T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v$

A)

$\frac{d(x,y)}{d(u,v)} =\left|\begin{array}{ccc}x_u&x_v\\y_u&y_v\end{array}\right|$

$=(\frac{56}{65} )^2+(\frac{33}{65} )^2\\\\=\frac{(56)^2+(33)^2}{(65)^2} \\\\=\frac{4225}{4225} \\\\=1$

B )

$S:-65 \leq u \leq 65, -65 \leq v \leq 65$

$T(65,65)=(x=\frac{56}{65} (65)-\frac{33}{65} (65),\ \ y =\frac{33}{65} (65)+\frac{56}{65} (65)\\\\=(23,89)$

$T(-65,65)=(-56-33,\ \ -33+56)\\\\=(-89,23)$

$T(-65,-65) = (-56+33,-33-56)\\\\=(-23,-89)$

$T(65,-65)=(56+33, 33-56)\\\\=(89,-23)$

C)

$\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}$

$=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(x^2+y^2)(\frac{d(x,y)}{d(u,v)} du\ \ dv$

Now

$x^2+y^2=(\frac{56}{65} u-\frac{33}{65} v)^2+(\frac{33}{65} u+\frac{56}{65} v)^2$

$[(\frac{56}{65} )^2+(\frac{33}{65}) ^2]u^2+[(\frac{33}{65} )^2+(\frac{56}{65}) ^2]v^2$

$=\frac{(65)^2}{(65)^2} u^2+\frac{(65)^2}{(65)^2} v^2=u^2+v^2$

$\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}$

$=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(u^2+v^2) du\ \ dv$

$=\int\limits^{65}_{-65}\int\limits^{65}_{-65}u^2du \ \ dv+\int\limits^{65}_{-65}\int\limits^{65}_{-65}v^2du \ \ dv$

By symmetry of the region

$=4\int\limits^{65}_0 \int\limits^{65}_0u^2 du \ \ dv + u\int\limits^{65}_0 \int\limits^{65}_0v^2 du \ \ dv$

$= 4(\frac{u^3}{3} )^{65}_{0}(v)_0^{65}+(\frac{v^3}{3} )^{65}_{0}(u)_0^{65}\\\\=4[\frac{(65)^4}{3} +\frac{(65)^4}{3} ]$

$=\frac{8}{3} (65)^4$

8 0

3 years ago

Can I get help with this???

exis [7]

5x + 13 + 3x + 7 = 180

8x +20 = 180

8x = 160

x = 20

7 0

3 years ago

A restaurant served 615 meals at lunch it then served 349 meals at dinner how many meals did the served all

Lyrx [107]

I’m pretty sure you just add 615 and 349 together which gets you 964 meals served all together

5 0

3 years ago

What is 37.5% of 81????

shepuryov [24]

It would be: 81*37.5 / 100 = 30.375

3 0

3 years ago

Read 2 more answers

The ratio of girls to boys at soccer practice is 3:4. If on Saturday there will be a total of 42 players, how many boys will be

Alex777 [14]

Answer:

$Boys = 24$

$Girls = 18$

Step-by-step explanation:

Given

$G:B= 3:4$

$Total = 42$

Required

Determine the number of boys and girls

We have to convert the ratio to fraction;

Number of girls can be calculated as:

$Girls = \frac{G}{G + B} * Total$

$Girls = \frac{3}{3 + 4} * 42$

$Girls = \frac{3}{7} * 42$

$Girls = 3 * 6$

$Girls = 18$

$Boys = Total - Girls$

$Boys = 42 - 18$

$Boys = 24$

3 0

3 years ago