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2 years ago

Please solve with explanation

Mathematics

1 answer:

Sindrei [870]2 years ago

6 0

I think the area is 59/2

I’m sorry if I’m wrong!! I used an app

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The area of a flower bed is 24 square feet. If the other sides were whole number demensions, how many lengths and widths are pos

goldenfox [79]

Answer:

The possible combinations are (4 & 6) ,(8 &3), (2 &12), (24 &1)

Step-by-step explanation:

The area of a flower bed is 24 square feet.

Now, the factors of 24 are 2 x 2 x 2 x 3.

Hence, if the other sides were whole number dimensions, then the possible combinations will be (4 & 6) ,(8 &3), (2 &12), (24 &1)

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4 years ago

292 tickets were sold for a basketball game, an adult ticket costs $3. A students ticket costs $1. Tickets sales were $470. How

Sliva [168]

Answer:

Step-by-step explanation:

8 0

3 years ago

Please help

sveta [45]

Based on the data given on the number pattern, 4 + 5 = 180

<h3>Number pattern</h3>

7 + 9 = 254016

3 + 7 = 7779240

5 + 8 = 2496000

7 + 9 = (7 × 9)^|7-9| × (7 + 9) × |7 - 9)

= 69² × 16 × 2

= 4761 × 16 × 2

= 254,016

3 + 7 = (3×7)^|3-7| × (3+7) × |3-7|

= 21⁴ × 10 × 4

= 194,481 × 10 × 4

= 7,779,240

So,

4 + 5 = (4×5)^|4-5| × (4+5) × |4-5|

= 20¹ × 9 × 1

4 + 5 = 180

Learn more about pattern of numbers:

brainly.com/question/6561461

#SPJ1

4 0

2 years ago

A simple random sample of 100 8th graders at a large suburban middle school indicated that 81% of them are involved with some ty

Sophie [7]

Answer:

The interval is $0.7187 < p < 2.421$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 100$

The population proportion is $p = 0.81$

The confidence level is C = 98%

The level of significance is mathematically evaluated as

$\alpha = 100 -98$

$\alpha = 2%$ %

$\alpha = 0.02$

Here this level of significance represented the left and the right tail

The degree of freedom is evaluated as

$df = n-1$

substituting value

$df = 100 - 1$

$df = 99$

Since we require the critical value of one tail in order to evaluate the 98% confidence interval that estimates the proportion of them that are involved in an after school activity. we will divide the level of significance by 2

The critical value of $\frac{\alpha}{2}$ and the evaluated degree of freedom is

$t_{df , \alpha } = t_{99 , \frac{0.02}{2} } = 2.33$

this is obtained from the critical value table

The standard error is mathematically evaluated as

$SE = \sqrt{\frac{p(1-p )}{n} }$

substituting value

$SE = \sqrt{\frac{0.81(1-0.81 )}{100} }$

$SE = 0.0392$

The 98% confidence interval is evaluated as

$p - t_{df , \frac{\alpha }{2} } * SE < p < p + t_{df , \frac{\alpha }{2} }$

substituting value

$0.81 - 2.33 * 0.0392 < p < 0.81 +2.33 * 0.0392$

$0.7187 < p < 2.421$

4 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

densk [106]

(-6,-2) or x-6 y-2.

7 0

3 years ago