I think it would just be 13 because T to U is 11 and U to V is 2 so if you want to find T to V you would add them together
Hope this helps in any way :))
22÷666= 0.03303303303303303303303303303303
Answer:
C. Three
Step-by-step explanation:
We want to solve the equation for n:
14,580 = 20,000(9/10)^n
14580/20000 = 729/1000 = (9/10)^n
(9/10)^3 = (9/10)^n . . . . . . write the left side as a cube
3 = n . . . . . . equate exponents
After year 3, the value will be $14,580.
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You can use logarithms to find n:
log(0.729) = n×log(0.9) . . . . . . taking the log of the 2nd line above
log(0.729)/log(0.9) = n = 3
9514 1404 393
Answer:
- 320 m after 8 seconds
- 5.6 seconds, 10.4 seconds to height of 290 m
Step-by-step explanation:
To find the height at 8 seconds, evaluate the formula for t=8.
S(t) = -5t^2 +80t
S(8) = -5(8^2) +80(8) = -320 +640 = 320
The height of the rocket is 320 meters 8 seconds after takeoff.
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To find the time to 290 meters height, solve ...
S(t) = 290
290 = -5t^2 +80t
-58 = t^2 -16t . . . . . . . divide by -5
6 = t^2 -16t +64 . . . . . complete the square by adding 64
±√6 = t -8 . . . . . . . . . take the square root
t = 8 ±√6 ≈ {5.551, 10.449}
The rocket is at 290 meters height after 5.6 seconds and again after 10.4 seconds.
Answer: The cube root of 10 is 2.1544 using an Xo value of -0.003723
Step-by-step explanation: The Newton-Raphson is a root finding method and its formula is NR: X=Xo-(f(x)/f'(x). Once you have the equation you also need to find the derivative of that equation before applying the formula. Since the problem stated that X =10, the method was applied to find the best root in order to find the cube root of 10 up to 5 significant figures. The best method is to use a software like Excel that helps you calculate those iterations faster. The root finding for this example was -0.003723.
