I need help with this!!!!!

Mathematics

1 answer:

Llana [10]2 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Find the distance between the points (-3, 11) and (5, 5).

marshall27 [118]

Formula for distance between two points:

d = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

   = √((5- -3)² + (5-11)²)

   = √((5+3)² + (5-11)²)

   = √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36

   = √(64 + 36)

= √(100)

= 10

Distance = 10 units.

5 0

3 years ago

1.Parallelogram ACFD is split in two parts so that ABED and FEBC are congruent isosceles trapezoids. What are the measures of al

DiKsa [7]

Refer to the diagram shown below.

Because ACFD is a parallelogram, its opposite angles are equal. Therefore
x = m∠ACF = m∠BCF = 48°
Similarly,
y = m∠CAD = m∠CFD

The sum of the angles inside a parallelogram is 360°. Therefore
48° + x + y + y = 360°
Because x = 48°,
48° + 48° + 2y = 360°
2y = 360° - 96° = 264°
y = 132°

Because ABED and FEBC are congruent, therefore
y = m∠DAB = m∠CFE = 132°
x = m∠ADE = m∠FCB = 48°

Because FEBC is a parallelogram, the opposite angles are equal. Therefore
m∠CBE = m∠CFE = y = 132°
m∠BCF = m∠BEF = x = 48°

Answer:
The measures of all angles of trapezoid FEBC are
m∠BCF = 48°
m∠BEF = 48°
m∠CBE = 132°
m∠CFE = 132°