Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
Refer to the diagram shown below.
Because ACFD is a parallelogram, its opposite angles are equal. Therefore
x = m∠ACF = m∠BCF = 48°
Similarly,
y = m∠CAD = m∠CFD
The sum of the angles inside a parallelogram is 360°. Therefore
48° + x + y + y = 360°
Because x = 48°,
48° + 48° + 2y = 360°
2y = 360° - 96° = 264°
y = 132°
Because ABED and FEBC are congruent, therefore
y = m∠DAB = m∠CFE = 132°
x = m∠ADE = m∠FCB = 48°
Because FEBC is a parallelogram, the opposite angles are equal. Therefore
m∠CBE = m∠CFE = y = 132°
m∠BCF = m∠BEF = x = 48°
Answer:
The measures of all angles of trapezoid FEBC are
m∠BCF = 48°
m∠BEF = 48°
m∠CBE = 132°
m∠CFE = 132°
Answer:
Step-by-step explanation:
Your question doesn't match the picture. OCR is often inaccurate!—not that it matters much in this case. None of the choices is correct.
(20-4)·6² + 2 + 18 = 16·6² + 2 + 18
= 16·36 + 2 + 18
= 576 + 2 + 18
= 578 + 18
= 596