A cafeteria offers oranges, apples, or bananas as its fruit option. It offers peas, green beans, or carrots as the vegetable option. Find the number of fruit and vegetable options. If the fruit and the vegetable are chosen at random. what is the probability of getting an orange and carrots? Is it likely or unlikely that a customer would get an orange and carrots?

Answer:

The probability of getting an orange and carrots is $\frac{1}{9}$

Step-by-step explanation:

The fruits offered in cafeteria = oranges, apples, or bananas.

The vegetables offered in cafeteria = peas, green beans, or carrots.

There are 3 fruits and 3 vegetables . Therefore the total possible number of outcomes is = $3 \cdot 3$ = 9

Now the probability of getting an orange and carrots = $\frac{1}{9}$

The possibility is very unlikely to happen

7 0

4 years ago

Which expression is equivalent to

miss Akunina [59]

D. 41x + 11y
You add the like terms so the 23 and 18 to equal 41

7 0

3 years ago

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Which parent function is represented by the graph?

Sergio [31]

Answer:

Linear

Step-by-step explanation:

pretty self explanatory

7 0

2 years ago

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Use the discriminant and select whether the roots of 4x 2 - 3x + 3 = 0 are real or imaginary.

MrRa [10]

To find the discriminant we use b^2 - 4ac

equation of 4x^2 - 3x + 3 = 0
a b c

-3^2 - 4 (4)(3) = -39
if b^2 - 4ac < 0, there are 2 complex roots or...no real roots...in this case imaginary.

8 0

4 years ago

Read 2 more answers