Question

What is the solution set of the following equation?

Answer 1

Multiply both sides by 5
4x^2=10x-4
divide both sides by 2
2x^2=5x-2
minus 5x from both sides and add 2 to both sides
2x^2-5x+2=0
use quadratic formula
for
ax^2+bx+c=0
x=$\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2-5x+2=0
a=2
b=-5
c=2
x=$\frac{-(-5)+/- \sqrt{(-5)^2-4(2)(2)} }{2(2)}$
x=$\frac{5+/- \sqrt{25-16} }{4}$
x=$\frac{5+/- \sqrt{9} }{4}$
x=$\frac{5+/- 3}{4}$
x=(5+3)/4 or (5-3)/4
x=8/4 or 2/4
x=2 or 1/2

3rd option is correct