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Kobotan [32]
3 years ago
8

Determine whether the following possible responses should be classified as interval, nominal or ordinal data.

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

1. Nominal data 2. Responses here can't be classified as interval or nominal or ordinal data 3.  Responses here can't be classified as interval or nominal or ordinal data  4. nominal

Step-by-step explanation:

1. Heidi's favorite  brand of tenis balls is only a "label" in the set of brands that can be regarded. So, because we are dealing with names or "labels" we should classify responses here as nominal data.

2. Possible values for the number of cars in a parking lot are 0, 1, 2, 3, 4,... Besides we can say that 4 cars is twice than 2 cars, and exist a true zero. We can't say that responses here correspond to interval data, in fact, we can say that responses here correspond to the kind of data called ratio data.

3. You can spend zero hours in your homework, so, there exists an absolute zero, besides, to say that you spend 4 hours in your homework is twice that if you spend 2 hours in your homework is meaningful. We can't classify responses here as interval data or ordinal or nominal. We can classify responses here as ratio data.

4. There are only two different responses here, i.e., You are a US citizen or You are not a US citizen. We are dealing with "labels" again, and in general, we can't say there is a better response or stablish an order.

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Find the perimeter of the object <br><br> Help step by step please!
aliina [53]

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

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