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2 years ago

6

Marvin has read 8% of the novel he started reading last Saturday. Which decimal is equivalent to the percentage of the novel Mar

vin has read?

1 answer:

timama [110]2 years ago

8 0

Answer:

0.8 or 0.08 i believe

Step-by-step explanation:

hope this helps!

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A town has a population of 13,000 and grows at 5% every year. What will be the population after 11 years to the nearest whole nu

timofeeve [1]

Answer:

So all you need to do is find 5% of 13000 which is 650.

Now 650 times 11= 7150

13000+ 7150=

20,150

6 0

3 years ago

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A garden table and a bench cost $985 combined. The garden table costs $35 more than the bench. What is the cost of the bench?

Papessa [141]

985-35=950, 950÷2=475, 475+35=510, 510 and 475

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3 years ago

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A square piece of fabric has an area of 595 cm2.

inna [77]

To find the length of the side, will take the under root of the area. So, the side will be :

c) 24.4 cm

8 0

3 years ago

Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) Without doing an

stepladder [879]

Answer:

Step-by-step explanation:

Given are 3 data sets with values as:

(i) 8 9 10 11 12 ... Mean =10

(ii) 7 9 10 11 13 ... Mean =10

(iii) 7 8 10 12 13 ... Mean =10

We see that data set shows mean deviations as

(i) -2 -1 0 1 2

(ii) -3 -1 0 1 3

(iii) -3 -2 0 2 3

Since variance is the square of std deviation, we find that std deviation is larger when variance is larger.

Variance is the sum of squares of (x-mean). Whenever x-mean increases variance increases and also std deviation.

Hence we find that without calculations also (i) has least std dev followed by (ii) and then (iii)

(i) (ii) (iii) is the order.

b) Between (i) and (ii) we find that 3 entries are the same and 2 entries differ thus increasing square by 9-4 twice. But between (ii) and (iii) we find that

increase in square value would be 4-1 twice. Obviously the latter is less.

6 0

3 years ago

Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b

77julia77 [94]

Answer:

The value is $UCL = 10.8$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 9 \ ounce$

The sample size is n = 25

The standard deviation is $\sigma = 3 \ ounce$

Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table

From the question we are told the confidence level is 99.7% , hence the level of significance is

$\alpha = (100 -99.7 ) \%$

=> $\alpha = 0.003$

Generally the degree of freedom is $df = n- 1$

=> $df = 25 - 1$

=> $df = 24$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of $df = 24$ is

$t_{\frac{\alpha }{2} , 24 } = 3.0$

Generally the margin of error is mathematically represented as

$E = t_{\frac{\alpha }{2} , 24} * \frac{\sigma }{\sqrt{n} }$

=> $E = 3.0 * \frac{3 }{\sqrt{25} }$

=> $E =1.8$

Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

$UCL = \= x + E$

=> $UCL = 9 + 1.8$

=> $UCL = 10.8$

4 0

2 years ago