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Natali [406]
3 years ago
7

Christine took 3 tests and had an average of 76. She has one more test to take and she wants an average of 80. What is the lowes

t score she can get on the last test? 10pts
Mathematics
1 answer:
amm18123 years ago
6 0

Answer: She has to score a minimum of 92 marks to take her average to 80

Step-by-step explanation:

Let the equation be

Three months total = 76 x 3 = 228

(x + 228) / 4 = 80

x + 228 = 80 x 4

x = 320 - 228

x = 92

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An artist is constructing a piece of art in the shape of rectangle. The artist wants to use string to tightly tie each vertex of
Liula [17]

Answer:

  65.8 ft

Step-by-step explanation:

The number of strings required to tie each vertex to the other three will be ...

  (4)(3)/2 = 6

Those strings will be perimeter strings plus two diagonal strings. The lengths of the perimeter strings are given as 12 ft and 7 ft. The lengths of the diagonal strings can be found using the Pythagorean theorem.

  d² = 12² +7² = 144 +49 = 193

  d = √193 ≈ 13.892

Then the total length of all strings is ...

  L = 2(12.0 +7.0 +13.9) = 65.8 . . . . feet

The artist will need 65.8 feet of string.

4 0
3 years ago
Pls help urgently extra points and mark brainlist
den301095 [7]

Answer:

the third one

Step-by-step explanation:

9 to the power of 4 is 9 multiplied by it's self 4 times

8 0
3 years ago
Look at problem 4. Will three soccer balls weigh more than 1 kilogram Explain
alex41 [277]

Answer:Yes

Step-by-step explanation:

So thats say each soccer ball weigh 450 grams and a kilogram is 1000 grams so we will do 450 times 3 which is 1350 and 1350 is more than 1000 grams which more than a killogram so the answer is yes and its by 350 more.

8 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
5/6 x− 5/12 x− 1/3 + 1/4 x+ 1/12
Helga [31]

5x/6-5/12, x-1/12, x+1/12

Step-by-step explanation:

3 0
3 years ago
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