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AysviL [449]
3 years ago
9

A miners' cage of mass 420 kg contains 3 miners of total mass 280 kg. The cage

Mathematics
1 answer:
svp [43]3 years ago
8 0

Answer:

5817 Newtons.

Step-by-step explanation:

Total mass of the cage + the miners = 700 Kg which is a downward force of  700g N.

The net downward force = 700g - T where T is the tension (force) in the cable. The g = acceleration due to gravity = 9.81 m s-2.

We  calculate the  acceleration of the cage by using an equation of motion:

Distance = ut + 1/2 a t^2     where u = initial velocity , t = time and a = acceleration:

75 = 0(t) + 1/2 a (10^2)

50a =  75

a = 1.5 m s-2.

So using Newtons second law of motion

Force = mass * acceleration:

700*9.81 - T = 700 * 1.5

T = 700 * 9.81 - 700*1.5

= 5817 N.

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A medication with an initial concentration of 1. 5 milligrams per liter is administered to a
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y

=

x

(

1

−

r

)

t

, half life of tablet is about

2

hours and after

t

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hours , remaining drug on patient's system is

42.875

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Step-by-step explanation: Initial drug

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r

=

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=

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Exponential model:

y

=

x

(

1

−

r

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t

=

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(

1

−

0.3

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t

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2

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log

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≈

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(

2

d

p

)

hour

The half life of tablet is about

2

hours.

After

t

=

3

hours , remaining drug on patient's system is

y

=

125

⋅

0.7

t

=

125

⋅

0.7

3

=

42.875

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2 years ago
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