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1 year ago

Create the Subset and Proper Subset of the set A= {1,2,3,4}. Upload your work.

Mathematics

1 answer:

kozerog [31]1 year ago

7 0

The subset of A is B = {1, 2} and the proper subset of A is C = {1,2,3,4}

<h3>How to create the Subset and Proper Subset of the set?</h3>

The set is given as:

A = {1,2,3,4}

Subsets of a set are sets that can be found in another set

An instance of this is

B = {1, 2}

Because all the elements of set B are in set A

Proper subsets of a set are sets that contain the exact elements found in another set

An instance of this is

C = {1,2,3,4}

Because set C and set A have the same elements

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29.06=? tenth + 6 hundredth

tankabanditka [31]

Answer:

Step-by-step explanation:

After the decimal point is the tenths place, and after the tenths place is the hundredths place.

After the decimal point is the number 0, which is at the tenths place. After the tenths place is 6, which is at the hundredths place.

8 0

3 years ago

The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they

Jobisdone [24]

The maximum profit is the y-coordinate of the vertex of the parabola represented by the equation.

$P(c)=-20c^2+320c+5120 \\ \\
a=-20 \\
b=320 \\ \\
\hbox{the vertex } (h,k): \\
h=\frac{-b}{2a}=\frac{-320}{2 \times (-20)}=\frac{-320}{-40}=8 \\
k=f(h)=f(8)=-20 \times 8^2+320 \times 8+5120= \\
=-1280+2560+5120=6400$

The maximum value is 6400, but the profit is given in hundreds of dollars, so multiply the value by 100.

The maximum profit the company can make is $640,000.

4 0

3 years ago

Read 2 more answers

The questions are in the photos, I know it's a lot but the question is worth 100 points. Please answer it,,,,

FromTheMoon [43]

Soooooo sorry but I only understood part a and c.

sorry

7 0

3 years ago

Read 2 more answers

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

8 0

3 years ago

How many sides does a regular (equal sides and equal angles) polygon have if each exterior angle measures 24°? # of sides =?

lubasha [3.4K]

If the measure of each exterior angle is 24, the measure of each interior angle is then 180-24=156
the sum of the interior angles of a polygon is (n-2)*180, n is the number of sides
(n-2)*180=156*n
180n-360=156n
24n=360
n=15
the polygon has 15 sides

5 0

3 years ago