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3 years ago

What are the coefficients in 8b-8b+3-3

Mathematics

2 answers:

otez555 [7]3 years ago

4 0

each of the ‘B’s in 8b

Step-by-step explanation:

it’s the B’s by 8 because a coefficient on google multiples letters or variables

ICE Princess25 [194]3 years ago

3 0

Answer: 8, -8, 3, and -3

Step-by-step explanation:

A coefficient is just a numeral placed before and multiplying the variable in an algebraic expression (e.x. 10 in 10xz).

So it would be 8, -8, 3, and -3

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What is the graph of f(x)=x^2-2x+3

Neko [114]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$f(x)=x^{2}-2x+3$

This is the equation of a vertical parabola open upwards

The vertex is a minimum

The vertex is the point (1,2)

The y-intercept is the point (0,3)

The function does not have x-intercepts

see the attached figure

7 0

3 years ago

___ are released that cause the cell to lyse or cytolysis

Vladimir79 [104]

Answer:

immune system

Step-by-step explanation:

I don't know exactly but I think the immune system

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2 years ago

Read 2 more answers

State if polygons are similar

sukhopar [10]

Yes similar polygons are are two polygons with the same shape but not the same size

8 0

3 years ago

Find the distance between the two points.

Ksenya-84 [330]

Hey there!

Distance formula:

d = $\sqrt{(x_{2}-x_{1})+(y_{2}-y_{1}) }$

Plug in variables:

d = $\sqrt{(0-(-6))+(0-(-7))}$

Simplify.

d = $\sqrt{6+7}$

d = $\sqrt{13}$

The distance between the two points is $\sqrt{13}$ units.

Hope this helps!

4 0

3 years ago

Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a

Vitek1552 [10]

Answer:

$2ab - 6a + 5b - 15$

Step-by-step explanation:

Given

$2ab - 6a + 5b + \_$

Required

Fill in the gap to produce the product of linear expressions

$2ab - 6a + 5b + \_$

Split to 2

$(2ab - 6a) + (5b + \_)$

Factorize the first bracket

$2a(b - 3) + (5b + \_)$

Represent the _ with X

$2a(b - 3) + (5b + X)$

Factorize the second bracket

$2a(b - 3) + 5(b + \frac{X}{5})$

To result in a linear expression, then the following condition must be satisfied;

$b - 3 = b + \frac{X}{5}$

Subtract b from both sides

$b - b- 3 = b - b+ \frac{X}{5}$

$- 3 = \frac{X}{5}$

Multiply both sides by 5

$- 3 * 5 = \frac{X}{5} * 5$

$X = -15$

Substitute -15 for X in $2a(b - 3) + 5(b + \frac{X}{5})$

$2a(b - 3) + 5(b + \frac{-15}{5})$

$2a(b - 3) + 5(b - \frac{15}{5})$

$2a(b - 3) + 5(b - 3)$

$(2a + 5)(b - 3)$

The two linear expressions are $(2a+ 5)$ and $(b - 3)$

Their product will result in $2ab - 6a + 5b - 15$

<em>Hence, the constant is -15</em>

3 0

3 years ago