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aliina [53]
3 years ago
8

A lamina occupies the part of the disk x2 + y2 ≤ 4 in the first quadrant. Find the center of mass of the lamina if the density a

t any point is proportional to the square of its distance from the origin. (x, y) =
Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer:sei

Step-by-step explanation:

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Can anyone help me with this problem?
Paraphin [41]

Answer:

(12, 0)

Step-by-step explanation:

The T4-5 means translate 4 units to the right and 5 units down.

So 8 + 4 = 12

5 - 5 = 0

The final answer is (12, 0)

Hope it helped!

4 0
3 years ago
What is the slope of the line of (6,22) and (15,55) please simplify​
Dennis_Churaev [7]

Answer:

11/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(55-22)/(15-6)

m=33/9

simplify

m=11/3

5 0
4 years ago
Lucas and his sister Luisa are saving to buy a birthday present for their mother. The present costs $95. Lucas earns $16 per wee
madreJ [45]
Your answer should be c

6 0
3 years ago
A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p
Kay [80]

Answer:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by V= 10 +t

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of \frac{A}{10+t}

So then we can reorder the differential equation like this:

\frac{dA}{dt} +\frac{A}{10+t} =8

We find the solution using the integration factor:

\mu = -\int \frac{1}{10+t} dt = -ln(10+t)

And then the solution would be given by:

A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})

And if we simplify this we got:

A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)

And after do the integral we got:

A= \frac{c}{10+t} +4 (10 +t)

And using the initial condition t=0 A= 20 we have this:

20 = \frac{c}{10} +40

c= -200

So then we have this function for the solution of A:

A= \frac{-200}{10+t} +4 (10 +t)

And now replacinf t= 40 we got:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

8 0
3 years ago
Using synthetic division, what is the factored form of this polynomial <br> x^3+3x^2-13x-15
kotegsom [21]

Answer:

D.

Step-by-step explanation:

(x-3)(x+1)(x+5)

3 0
3 years ago
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