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2 years ago

What is a way to find what 7 is what percent of 20 and I can't use a percent bar model?

Mathematics

1 answer:

Viefleur [7K]2 years ago

6 0

Answer:

you can cross multiply or u can 7/20 to get the answer that 7 is 35% of 20

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I like turtles so how fast can a turtle cross the street if it was going 2 mils per hour and 2,934,000 hours past?

Studentka2010 [4]

Answer:

5,868,000

Step-by-step explanation:

2,934,000 x 2 = 5,868,000

3 0

3 years ago

Please please help me

Anarel [89]

so you are going to use the Pythagorean theorem on the smaller triangle to find the connecting side's length

${5}^{2} = {3}^{2} ( {b}^{2} ) \\ b = 4$

now you can find the bigger triangle's hypotenuse

${6}^{2} + {4}^{2} = {c}^{2} \\$

c=4

8 0

2 years ago

Find the height of a rectangle with a base of 11 in and area of 120 in2

Mrac [35]

Answer:

that is the solution to the question

3 0

3 years ago

given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a ration

Vedmedyk [2.9K]

Answer:

$\tan(A) = \frac{3}{5}$

Step-by-step explanation:

Given

$\sin(A) = \frac{3}{\sqrt {34}}$

$0 \le A \le 90$ --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

$\tan(A) = \frac{Opposite}{Hypotenuse}$

and

$\sin(A) = \frac{3}{\sqrt {34}}$

By comparison:

$Opposite = 3$

$Hypotenuse = \sqrt{34$

So, the Adjacent is:

$Hypotenuse^2 = Adjacent^2 + Opposite^2$

$(\sqrt{34})^2 = Adjacent^2 + 3^2$

$34 = Adjacent^2 + 9$

Collect like terms

$Adjacent^2 =34 - 9$

$Adjacent^2 =25$

Take square roots

$Adjacent =\sqrt{25$

$Adjacent =5$

The tangent of an angle is:

$\tan(A) = \frac{Opposite}{Adjacent}$

This gives:

$\tan(A) = \frac{3}{5}$

8 0

3 years ago

What’s the volume of the pyramid

ValentinkaMS [17]

Answer:

The volume of the given pyramid is 300 cm³

Step-by-step explanation:

The volume of a pyramid, $V_{pyramid}$ , is given as follows;

$V_{pyramid} = \dfrac{1}{3} \times Base \ area \times Height$

The height of the pyramid = 12 cm

The side length of the square base of the pyramid = 5 cm

The base area of the pyramid polyhedron with square base = 5 cm × 5 cm = 25 cm²

Therefore, by substitution, we have;

$V_{pyramid} = \dfrac{1}{3} \times 25 \ cm^2 \times 12 \ cm = 300 \ cm^3$

The volume of the given pyramid, V = 300 cm³.

5 0

2 years ago