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4 years ago

Rewrite the fraction in simplest form. 40/56

2 answers:

8 0

First, find the greatest common factor. That is 8.

Divide both numbers by 8.

40 ÷ 8 = 5
56 ÷ 8 = 7

The simplest for of this fraction is: 5/7

Vikentia [17]4 years ago

5 0

You can divide both 40 and 56 by 8. You'll have then (40 ÷ 8) / (56 ÷ 8)= 5/7 which is the simplest form of the fraction.

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How to simplify 45/100

fredd [130]

-- Look for a common factor of both the top and bottom numbers.

   ==> 5 is a common factor of 45 and 100 .

-- Divide the top and bottom numbers by their common factor.

   ==> 45/100 = 9/20 .

-- Look for another common factor of both the top and bottom numbers.

   ==> The only common factor now is ' 1 ' .

   ==> That means the fraction is now as simplified as it can get.

6 0

3 years ago

Use the FOIL pattern to find the product.

blsea [12.9K]

Answer:

Step-by-step explanation:

First

Outer

Inner

Last

3x*3x=9x^2

3x*-8=-24x

6*3x=18x

6*-8=-48

9x^2-24x+18x-48

9x^2-6x-48

7 0

4 years ago

Over the first five years of owning a car Gina drove about 12200 miles the first year 16211 miles the second year 12050 the thir

Nataly_w [17]

Mean (average) - 13027.2
Median (middle number) - 12,200
Mode (occurs the most often) - none of the numbers occur more than once?

Mean would be the best to predict because it is the average miles Gina has driven over the past five years

3 0

4 years ago

Wayne's service center operates a welding shop. Assume that the arrival of jobs follows a Poisson distribution with 2 jobs arriv

Reika [66]

Answer:

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

The mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour

a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

$L=\frac{\lambda^2\sigma^2+(\lambda/\mu)^2}{2(1-\lambda/\mu))} =\frac{0.25^2*0.2^2+(0.25/0.3125)^2}{2(1-0.25/0.3125)}=2.225\ hours$

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

$W_q=\frac{L}{\lambda}=2.225/0.25=8.9\ hours$

d) The average number of hours between when a job is received and when it is completed (W) is given as:

$W=W_q+\frac{1}{\mu} =8.9+\frac{1}{0.3125}=12.1 \ hours$

e) Percentage of the time is Gubser's welder busy (P) is given as:

$P=\frac{\lambda}{\mu}=0.25/0.3125=0.8=80\%$

4 0

3 years ago

What is the answer to the equation 1 + 1

Ivahew [28]

Answer:

or.....

2?!?!

Step-by-step explanation:

!!!!!!!!!

8 0

3 years ago