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a_sh-v [17]
3 years ago
15

The distribution of actual weights of 8 oz. wedges of cheddar cheese produced at a dairy is Normal with mean 8.1 ounces and stan

dard deviation 0.2 ounces. A sample of 10 of these cheese wedges is selected. What is the standard deviation of the sampling distribution of the mean
A. approximately Normal, mean 8.1, standard deviation 0.2.
B. approximately Normal, mean 8.1, standard deviation 0.020.
C. It is not possible to tell because the sample size is too small.
D. approximately Normal, mean 8.1, standard deviation 0.063.
Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

C THE ANSWER I THINK WHY U THINK JK LOL

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What two numbers multiply 45 and add to 14
xxMikexx [17]


Ok to start this problem you must list two numbers that add to 14

7 and 7

9 and 5

10 and 4

6 and 8

those are the numbers that we will use for now..

Now multiply each pair of numbers and see which one equals 45

7 * 7 = 49, no

9 * 5 = 45, YES

10 * 4 = 40, No

6 * 8 = 48, No


The numbers discovered are 9 and 5

5 0
3 years ago
Simplify (5^x+2-5^x)/5^x×4
murzikaleks [220]

Answer:

6

Step-by-step explanation:

The given expression is,

\frac{5^{x+2}-5^x }{5^x\times4}

Now, we know that,

a^{m+n} = a^m . a^n

Then,

5^{x+2}=5^x . 5^2

So,

\frac{5^{x+2}-5^x}{5^x\times4}=\frac{5^x.5^2-5^x}{5^x\times4}

Now, taking 5^{x} common from the numerator of the given expression, then

\frac{5^{x+2}-5^x}{5^x\times4}=\frac{5^x(5^2-1)}{5^x\times4}

\implies\frac{5^{x+2}-5^x }{5^x\times4}=\frac{5^2-1}{4}

\implies\frac{5^{x+2}-5^x}{5^x\times4}=\frac{5\times5-1}{4}=\frac{25-1}{4}

\implies\frac{5^{x+2}-5^x}{5^x\times4}=\frac{24}{4}=6

So, the simplified form of the given expression gives the result 6.

8 0
4 years ago
Talia tossed a penny many times; she got 40 heads and 60 tails. What is the probability of Talia getting heads?
disa [49]
Her probability is 4/10 times.
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Find the discriminant and the number of real roots for x^2+2x+8=0
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Answer:

Discriminant: -28

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