Question

Peter leaves Mitchell's house traveling 30 mph. Mitchell leaves 15 min later, trying to catch up to peter, going 40 mph, if they drive along the same route how long will it take Mitchell to catch Peter?

Answer 1

Given :

Peter velocity , P = 30 mph .

Mitchell velocity , M = 40 mph .

Mitchell leaves 15 min later .

To Find :

If they drive along the same route how long will it take Mitchell to catch Peter.

Solution :

Distance covered by Peter in 15 min .

$D = 30\times \dfrac{15}{60}=7.5\ miles$

Let , time taken is x .

So , distance covered b them is equal :

$7.5+30\times x=40\times x\\\\x=\dfrac{7.5}{10}=0.75\ hours\\\\x=0.75\times 60\ min\\\\x=45\ min$

Therefore , time taken by them is 45 minutes .

Hence , this is the required solution .