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madreJ [45]
3 years ago
12

The temperature of a chemical solution is originally 21^\circ\text{C}21 ? C21, degree, C. A chemist heats the solution at a cons

tant rate, and the temperature of the solution is 75^\circ\text{C}75 ? C75, degree, C after 121212 minutes of heating.
Mathematics
1 answer:
Kryger [21]3 years ago
5 0

Answer:

The rate is 4.5\frac{\°C}{min}

Step-by-step explanation:

we know that

The formula to calculate the rate or slope between two points is equal to m=\frac{y2-y1}{x2-x1}

Let

x----> the time in minutes

y-----> the temperature in Celsius degrees

we have

A(0,21)\ B(12,75)

Substitute the values

m=\frac{75-21}{12-0}

m=\frac{54}{12}=4.5\frac{\°C}{min}

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Find the mode of this data set:<br> 31, 30, 32, 31, 30, 31, 32,<br> 33, 30, 31, 31, 30, 32
MariettaO [177]

Answer:

31 is the mode of the data as it appears 5 times

4 0
3 years ago
Pretty please help I’m timed
Alex

Answer:

First one...

Step-by-step explanation:

Welp I mean if you look at the numbers -12, -3 and 7 you can see how they corrspoond to the points plotted on the first number line.

3 0
3 years ago
Read 2 more answers
Simplify: 6(x-2y) - 3(2x+y)
Hitman42 [59]

Answer: -15y

Step-by-step explanation:

6(x-2y) - 3(2x+y)

6x-12y -6x-3y

0x -15y

-15y

5 0
2 years ago
Read 2 more answers
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0
3 years ago
On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 9 k
nadya68 [22]

Answer:

6 kg

Step-by-step explanation:

Given is weight of an object directly varies with the mass of the object .

Let the constant of proportionality be k

So,

Weight = K×(mass of the object)

For an object , weight = 45 N

                        mass = 9 kg

So , 45 = K×9

      K = 5.

Now, for the other object ,

Weight = 30 N. K = 5 (as obtained above)

So, 30 = 5×(mass of the object)

mass of the object = 6 kg.

5 0
3 years ago
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