Question

The temperature of a chemical solution is originally 21^\circ\text{C}21 ? C21, degree, C. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ? C75, degree, C after 121212 minutes of heating.

Answer 1

Answer:

The rate is $4.5\frac{\°C}{min}$

Step-by-step explanation:

we know that

The formula to calculate the rate or slope between two points is equal to $m=\frac{y2-y1}{x2-x1}$

Let

x----> the time in minutes

y-----> the temperature in Celsius degrees

we have

$A(0,21)\ B(12,75)$

Substitute the values

$m=\frac{75-21}{12-0}$

$m=\frac{54}{12}=4.5\frac{\°C}{min}$