Find the mode of this data set:<br>
31, 30, 32, 31, 30, 31, 32,<br>
33, 30, 31, 31, 30, 32
MariettaO [177]
Answer:
31 is the mode of the data as it appears 5 times
Answer:
First one...
Step-by-step explanation:
Welp I mean if you look at the numbers -12, -3 and 7 you can see how they corrspoond to the points plotted on the first number line.
Answer: -15y
Step-by-step explanation:
6(x-2y) - 3(2x+y)
6x-12y -6x-3y
0x -15y
-15y
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Answer:
6 kg
Step-by-step explanation:
Given is weight of an object directly varies with the mass of the object .
Let the constant of proportionality be k
So,
Weight = K×(mass of the object)
For an object , weight = 45 N
mass = 9 kg
So , 45 = K×9
K = 5.
Now, for the other object ,
Weight = 30 N. K = 5 (as obtained above)
So, 30 = 5×(mass of the object)
mass of the object = 6 kg.
