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mojhsa [17]
3 years ago
11

Can someone help me with 39 and 40?

Mathematics
2 answers:
loris [4]3 years ago
6 0
39.
9.2 x 10^3, 10,000, 1.8 x 10^4


40.
0.005, 5.25 x10^-3, 5.0 x 10^-2
faltersainse [42]3 years ago
6 0

39. Since exponents with 10 give us the number of zeros we are working with ex.(10^3= 1000, 3 zeros) We can just find out what we need to multiply and we can order them. 9.2x 1000= 9200. Now we just need to find the last one, being 10^4= 10,000x 1.8= 18,000. Now we order them: 9,200, 10,000, 18,000.


40. The same rule about working with exponents can be said when working with negative exponents but instead of how many zeros we add, it's how many zeros we take a step to the left from (ex. 10^-4= 0.0001, 4 zeros back.) So we just find the exponents' real value and work with them. 5.25 x 0.001= 0.00525. 5 x 0.01= 0.05. Now we order them: 0.005, 0.00525, 0.05

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0 gram setting. It
MrRa [10]

Answer:

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of the Population(μ) = 449

The Standard deviation of the population(σ) = 22

size of the sample 'n' = 36

mean of the sample(x⁻) = 444

Given the level of significance(α) = 0.1

Critical value Z = 1.645

<u><em>Step(ii):</em></u>-

<em>Null hypothesis</em>:H₀:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0

(μ) = 449

<em>Alternative Hypothesis</em>:H₁: (μ) ≠ 449

Test statistic

                  Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } } \\= \frac{444-449}{\frac{22}{\sqrt{36} } }

                 = -1.36

<em>Final answer:-</em>

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

5 0
2 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

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alex41 [277]

Answer:

1/8, 0.0625 , or 6.25%

Step-by-step explanation:

50% of the cars are painted white.

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Probability of A occuring 4 time(s) = 0.54 = 0.0625

Probability of A NOT occuring = (1 - 0.5)4 = 0.0625

Probability of A occuring = 1 - (1 - 0.5)4 = 0.9375

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Answer:

it is a two-dimensional shape that can be modified to form a three-dimensional shape or a solid

Step-by-step explanation:

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7 0
3 years ago
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