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3 years ago

Can someone help me with 39 and 40?

Mathematics

2 answers:

loris [4]3 years ago

6 0

39.
9.2 x 10^3, 10,000, 1.8 x 10^4

40.
0.005, 5.25 x10^-3, 5.0 x 10^-2

faltersainse [42]3 years ago

6 0

39. Since exponents with 10 give us the number of zeros we are working with ex.(10^3= 1000, 3 zeros) We can just find out what we need to multiply and we can order them. 9.2x 1000= 9200. Now we just need to find the last one, being 10^4= 10,000x 1.8= 18,000. Now we order them: 9,200, 10,000, 18,000.

40. The same rule about working with exponents can be said when working with negative exponents but instead of how many zeros we add, it's how many zeros we take a step to the left from (ex. 10^-4= 0.0001, 4 zeros back.) So we just find the exponents' real value and work with them. 5.25 x 0.001= 0.00525. 5 x 0.01= 0.05. Now we order them: 0.005, 0.00525, 0.05

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0 gram setting. It

MrRa [10]

Answer:

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

Step-by-step explanation:

Step(i):-

Given mean of the Population(μ) = 449

The Standard deviation of the population(σ) = 22

size of the sample 'n' = 36

mean of the sample(x⁻) = 444

Given the level of significance(α) = 0.1

Critical value Z = 1.645

Step(ii):-

Null hypothesis:H₀:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0

(μ) = 449

Alternative Hypothesis:H₁: (μ) ≠ 449

Test statistic

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } } \\= \frac{444-449}{\frac{22}{\sqrt{36} } }$

= -1.36

Final answer:-

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

5 0

2 years ago

Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,

vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0) is a saddle point

C(3,0) is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is

$f(x,y)=x^3+y^3-3x^2-3y^2-9x$

The first partial derivative with respect to x is

$f_x=3x^2-6x-9$

The first partial derivative with respect to y is

$f_y=3y^2-6y$

We now set each equation to zero to obtain the system of equations;

$3x^2-6x-9=0$

$3y^2-6y=0$

Solving the two equations simultaneously, gives;

$x=-1,x=3$ and $y=0,y=2$

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

$D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2$

But, we would have to calculate the second partial derivatives first.

$f_{xx}=6x-6$

$f_{yy}=6y-6$

$f_{xy}=0$

$\Rightarrow D=(6x-6)(6y-6)-0^2$

$\Rightarrow D=(6x-6)(6y-6)$

At A(-1,0),

$D=(6(-1)-6)(6(0)-6)=72\:>\:0$ and $f_{xx}=6(-1)-6=-18\:$

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

$D=(6(-1)-6)(6(2)-6)=-72\:$

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

$D=(6(3)-6)(6(0)-6)=-72\:$

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

$D=(6(3)-6)(6(2)-6)=72\:>\:0$ and $f_{xx}=6(3)-6=12\:>\:0$

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0

3 years ago

At a local dealership 30% of cars are SUVs, 50% of the cars are painted white, and 15% are white and an SUV. If we randomly sele

alex41 [277]

Answer:

1/8, 0.0625 , or 6.25%

Step-by-step explanation:

50% of the cars are painted white.

1/2 * 1/2 = 1/4 * 1/4 = 1/8

Probability of A occuring 4 time(s) = 0.54 = 0.0625

Probability of A NOT occuring = (1 - 0.5)4 = 0.0625

Probability of A occuring = 1 - (1 - 0.5)4 = 0.9375

6 0

3 years ago

What is a net in math?

WITCHER [35]

Answer:

it is a two-dimensional shape that can be modified to form a three-dimensional shape or a solid

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help with this problem

cupoosta [38]

$\bf \begin{cases}
(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12
\\
&\qquad \uparrow \\
&\textit{same bases, thus}\\
&\qquad \downarrow 
\\
n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6
\end{cases}
\\\\\\
thus\implies 
\begin{cases}
4p=12\implies p=\frac{12}{4}
\\\\
3+q=6\implies q=6-3
\end{cases}
\\\\

\\\\
then\implies p\cdot q=\boxed{?}$

7 0

3 years ago