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AnnZ [28]
4 years ago
12

Teri is downloading a file on the computer shows this image after taking two minutes to download about how long will it take Ter

ry to download the whole file
Mathematics
1 answer:
torisob [31]4 years ago
8 0
4 min because it took tow so I added tow more
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Becky buys a notebook for $1.59 and pens for $0.29 each. She spends $5.07. Assume there is no sales tax where Becky lives.
Mekhanik [1.2K]

Answer:

Not sure

Step-by-step explanation:

3 0
3 years ago
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Jake recorded a special album in honor of Mothers Day. His mom was so excited she purchased 40% of the copies in true store. She
Ludmilka [50]

The answer is 200.

40% = 80

40%/4 = 80/4

10% = 20

10% • 10 = 20 • 10

100% = 200

Hope this helps!

If it does consider making it brainliest as it helps me out.

4 0
3 years ago
Please help me and my son I am confused
Agata [3.3K]

Answer:

-13p^{4} - 8p^{2} + 4p + 3

Step-by-step explanation:

I am having a little trouble reading the number.  I think 5 is the question number and not part of the problem.  I think this is the problem:

(4p - 6p^{4} - 3) - (8p^{2} + 7p^{4} - 6)  You take the opposite of everything inside the second set of parentheses.  You can think of it as multiplying through by -1

4p - 6p^{4} - 3 - 8p^{2} - 7p^{4} + 6  Now we combine like terms.  That is the numbers with the same variable p and the same power of p.

-13p^{4} - 8p^{2} + 4p + 3

4 0
2 years ago
Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
7 0
3 years ago
What is the solution to this system of equations?
labwork [276]

Answer:

C

Step-by-step explanation:

C. x=7, y=5

4 0
2 years ago
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