if x=t^2-1 and y=t^4-2t^3, then when t=1 what's d^2y/dx^2? if x=t^2-1 and y=t^4-2t^3, then when t=1 what's d^2y/dx^2?
1 answer:
<span>The solution to the problem is as follows: d^2y/dx^2 = d/dt(dy/dx) * dt/dx = d/dt (2t^2 - 3t) * dt/dx = ( 4t-3) * 1 / 2t = (4t-3)/2t when t = 1 d^2y/dx^2 = 1/2 I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! </span>
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