Question

if x=t^2-1 and y=t^4-2t^3, then when t=1 what's d^2y/dx^2? if x=t^2-1 and y=t^4-2t^3, then when t=1 what's d^2y/dx^2?

Answer 1

The solution to the problem is as follows:

d^2y/dx^2    = d/dt(dy/dx) * dt/dx

                      = d/dt (2t^2 - 3t) * dt/dx

                      = ( 4t-3) * 1 / 2t = (4t-3)/2t

when t = 1 d^2y/dx^2 = 1/2


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