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Dafna1 [17]
3 years ago
11

Insert 6 arthematic mean between 5 and -9​

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Consider 5 and - 9 to be terms in an arithmetic sequence and we require to find the 6 terms between them.

The n th term of an arithmetic sequence is

a_{n} = a + (n - 1)d ← d is required

Here a = 5 and a_{8} = - 9, hence

5 + 7d = - 9 ( subtract 5 from both terms )

7d = - 14 ( divide both sides by 7 )

d = - 2

---------------------------------------------------------

The terms in the sequence are

5, 5 - 2, 5 - 4, 5 - 6, 5 - 8, 5 - 10, 5 - 12, - 9 , that is

5, 3, 1, - 1, - 3, - 5, - 7, -9

With the 6 arithmetic means being

3, 1, - 1, - 3, - 5, - 7

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What two numbers equal -114
Paraphin [41]

Answer:

-57+-57

-57•2

Step-by-step explanation:

4 0
3 years ago
find the nearest two positive coterminal angles and the nearest two negative coterminal angles for 420°
RSB [31]

Answer:

Positive Coterminal Angles = 60°,780°

Negative Coterminal Angles = -300°, -660°

Step-by-step explanation:

<h3>Positive Coterminal Angles:</h3>

To find nearest two coterminal angle of 420°:

1) Subtract 360° from 420°:

420°- 360° = 60° (First Positive Coterminal Angle)

2)Add 360° to 420°:

420°+ 360° =780° (Second Positive Coterminal Angle)

<h3>Negative Coterminal angles:</h3>

To find nearest two negative coterminal angles of 420°. We' lave to take the value below 0.

1) Substract 360° from 420°

420°- 360° = 60°

Which is still a positive value.

2) Again Substract 360° from 60°

60°- 360° = -300° (First Negative Coterminal Angle)

3)Subtract 360° from -300°

-300°- 360° = -660° (Second Negative Coterminal Angle)

3 0
3 years ago
A man bought 420 apples for Rs. 280 but 84 were rotten. Yet he earned 20%. Estimate how did he sell ?
Sav [38]
420-84=336(total apples sold)

280*0.2=56Rs.(earned)

280+56=336Rs.(total sale)

336/336=1 Rs (sold one for 1 Rs.)



4 0
3 years ago
Determine the horizontal change of a line with an x-intercept at (-5, 0) and a y-intercept at (0, 4). Type a numerical answer in
klasskru [66]

Answer:

  5

Step-by-step explanation:

The difference of x-values is the horizontal change:

  0 -(-5) = 5

3 0
3 years ago
what is the equation of the quadratic function that passes through the points (0,-1),(1,0),and (2,-3)
Alexus [3.1K]

Answer:

-2x^2 + 3x -1

Step-by-step explanation:

y = ax^2 + bx + c

(0,-1):  

-1 = a(0)^2 + b(0) + c

-1 = 0 + 0 + c

-1 = c

(1,0):

0 = a(1)^2 + b(1) + c

0 = a + b + c

(2,-3):

-3 = a(2)^2 + b(2) + c

-3 = 4a + 2b + c

Replace c with -1

0 = a + b -1

1 = a + b

-3 = 4a + 2b -1

-2 = 4a + 2b

-1 = 2a + b

Solve:

2a + b = -1

-1a - b = -1

a = -2

2a + b = -1

-2a -2b = -2

-b = -3 divide both by -1:  b = 3

a = -2; b = 3; c = -1

y = ax^2 + bx + c or y = -2x^2 +3x -1

6 0
3 years ago
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