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jarptica [38.1K]
3 years ago
6

Angelica was selling her blankets for $85 each. She wanted to make more money so she raised her price by 20%. Her

Mathematics
1 answer:
larisa [96]3 years ago
7 0

Answer:

26

Step-by-step explanation:

this is it I did 100 calculations per second and found it

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What is the equation of the line that passes<br> through the points (4, -3) and (2, 3).
Minchanka [31]

Answer:

24

Step-by-step explanation:

(4-3) + (23) = 24

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3 years ago
Step 5: Determine the intersection point: approximately (-9,-2)
BabaBlast [244]

Answer:

B

Step-by-step explanation:

Because when you add negitives to negitives it then becomes a positive for the y intercept.

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Need help plz I’m almost done
JulsSmile [24]

Hello!


The graph, (2/5)^x is an exponential function.


Since there is not a negative symbol in the front of the function, options A and B are incorrect.


For option 3 to be correct, there would need to be a negative symbol in front of the exponent, x.


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8 0
3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

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3 years ago
I need to know how to do these!!
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The four would go under neith in the left hand side but I don’t know how to explain it
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