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3 years ago

5(2+x)+2=32 what is x

Mathematics

1 answer:

pentagon [3]3 years ago

4 0

10+5x+2=32 5x+12=32 5x=20 x=4

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Which of the following best describes the function shown below?

Andrei [34K]

Answer: I need to see the picture of the work first to tell u

Step-by-step explanation:

6 0

3 years ago

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Distribute and combine like terms. 3(2x - 7) +5

NeTakaya

When you distribute, it would be 6x - 21 + 5

-21 + 5 = -16

this means the answer would be left as 6x - 16

6 0

3 years ago

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One Friday night, two large groups of people called Weston Taxi Service. The first group requested 2 sedans and 1 minivan, which

muminat

Answer:

Sedan: 4 passengers

Minivan: 6 passengers

Step-by-step explanation:

We can write the following system of equations:

$\begin{cases}2s+1m=14 \\2s+2m=20\end{cases}$ , where $s$ represents the number of people a sedan can seat and $m$ represents the number of people a minivan can seat.

Subtracting the first equation from the second, we have:

$2s+2m-(2s+1m)=20-14,\\\\m=6$

Now plug in $m=6$ in any of the equations to solve for $s$ :

$2s+1(6)=14, \\2s=8, \\s=4$

Verify that the solution pair $(4, 6)$ works:

$2(4)+1(6)=14\: \checkmark \\2(4)+2(6)=20 \: \checkmark$

Therefore, a sedan can hold 4 passengers and a minivan can hold 6 passengers.

4 0

3 years ago

Find the quotient of 2.632 · 104 and 2 · 10-7.

faust18 [17]

2.632 x 10^4 ÷ 2 x 10-7 =

1.316 x 10^11

5 0

4 years ago

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How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif

konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

Solution:

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

$x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440$

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0

3 years ago