Answer:
The code to this question can be given as:
Code:
while ((s!="Y" && s!="y" && s!="N" && s!="n")) //loop for check condition
{
cin >> s; //insert value
}
Explanation:
The description of the following code:
- In this code, we use a string variable s that has been to define in question.
- In code, we use a while loop. It is an entry control loop in loop we check variable s value is not equal to "y", "Y", "n" and "N".
- In the loop we use AND operator that checks all value together. If this is true So, we insert value-form user input in string variable that is "s".
Overflow occurs when the magnitude of a number exceeds the range allowed by the size of the bit field. The sum of two identically-signed numbers may very well exceed the range of the bit field of those two numbers, and so in this case overflow is a possibility.
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.