Answer:
Explanation:
The following Python program has a function called addDigits which takes a number as a parameter and returns the sum of the digits. Then the program creates a loop that keeps creating random numbers between 222 and 1000 and divides it by the value returned from the function addDigits. If the remainder is 0 is prints out a statement and breaks the loop, ending the program. The picture below shows the output of the program.
import random
def addDigits(num):
sum = 0
for x in str(num):
sum += int(x)
return sum
sum = addDigits(random.randint(222, 1000))
while True:
myRandomNum = random.randint(2, 99)
if (sum % myRandomNum) == 0:
print("No remainder between: " + str(sum) + " and " + str(myRandomNum))
break
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above
32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
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