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Sloan [31]
3 years ago
7

15 Points!!! Plzz Help!! Hurry!! Will Give Brainliest!!!!

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

there isnt much explaination for it


Brilliant_brown [7]3 years ago
5 0

Answer:

Hmm, this one is confusing. Try B, it seems most probable.

Step-by-step explanation:


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Complete the table of values fory=2x^2+x
Semmy [17]

Complete question:

y = 2x² + 2x - 3

x = -2 -1 0 1 2

Answer:

<u>Complete table of values</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

Step-by-step explanation:

Given;

y = 2x² + 2x - 3

To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.

when, x = -2

y = 2(-2)² + 2(-2) - 3

y = 8 - 4 - 3

y = 1

when x = -1

y = 2(-1)² + 2(-1) - 3

y = 2 - 2 - 3

y = -3

when x = 0

y = 2(0)² + 2(0) - 3

y = 0 - 0 - 3

y = -3

when x = 1

y = 2(1)² + 2(1) - 3

y = 2 + 2 - 3

y = 1

when x = 2

y = 2(2)² + 2(2) - 3

y = 8 + 4 - 3

y = 9

<u>Complete table</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

7 0
2 years ago
Estimate the area of a circle with a radius of 3.1 feet
Aliun [14]

Answer:

Step-by-step explanation:

Area of a circle = pi x square of radius = 30.190 ft

5 0
3 years ago
Stuck on this problem
zysi [14]

step 2 would be 10

step 4 would be 10x-x = 9x =7

 x = 7/9

6 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through (4, 9) and (6, 10).
kramer

Step-by-step explanation:

Slope (m) =ΔYΔX=12=0.5θ =arctan(ΔY)ΔX=26.565051177078°ΔX = 6 – 4 = 2ΔY = 10 – 9 = 1Distance (d) = √ΔX2 + ΔY2 = √5

= 2.2360679774998

4 0
2 years ago
3)
Wewaii [24]

Answer:

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

Step-by-step explanation:

Given -

\frac{1}{3} volume of sand in bucket is able to cover \frac{1}{9} area of the entire playground

Thus,

For covering  \frac{1}{9} unit area of the entire playground, the amount of sand required is equal to  \frac{1}{3}  of the total volume of sand in bucket

For covering  1 unit area of the entire playground, the amount of sand required is equal to

\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3}  * \frac{9}{1} \\\frac{9}{3}\\= 3

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

4 0
3 years ago
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