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kow [346]
3 years ago
7

Use the divisibility rules to determine which of the following numbers 504 is divisible by.

Mathematics
1 answer:
Reika [66]3 years ago
3 0

Answer:

504 is divisible by 2, 3, and 7. It is not divisble by 5 or 11

Step-by-step explanation:

C'mon. Use a calcultor.

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Scores on a test have a mean of 78.2 and 8 percent of the scores are above 89. The scores have a distribution that is approximat
anyanavicka [17]

Answer:

The standard deviation is 7.7

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 78.2

8 percent of the scores are above 89

This means that X = 89 has a pvalue of 1 - 0.08 = 0.92. So when Z = 89, Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{89 - 78.2}{\sigma}

1.405\sigma = 10.8

\sigma = \frac{10.8}{1.405}

\sigma = 7.7

The standard deviation is 7.7

5 0
3 years ago
How do you solve 34=1/2H(10+7)
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Multiply to remove the variable from the denominator. h= 1/4
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Jill got 36 out of 40 questions correct on her test. What percent of her test did she get correct?
ale4655 [162]

Answer:

36 percent I think ya

Step-by-step explanation:

I think I should know this

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What is the midpoint of the segment shown below?
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The sixteenth one which is
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Which ordred pair is in the solution set of 4x + 8y>16 ?
ss7ja [257]

yes thats fab Step-by-step explanation:

The perimeter of a rectangle is 46 inches. If the width of the rectangle is 9 inches, what is the length?

A.  

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B.  

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D.  

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