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Induced pluripotent stem cells are cells from adults that have been reprogrammed to imitate embryonic stem cells. Why might indu

FinnZ [79.3K]

Induced pluripotent stem cells can be a valuable tool in science and medicine because: A. induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells.

A cell can be defined as the fundamental functional, structural and smallest unit of life, which is typically found in all living organisms.

In Science, all living organisms are broadly grouped into two (2) main categories according to cell type and these include the following;

Unicellular organisms

Multicellular organisms

Basically, the reason why induced pluripotent stem cells can be a valuable tool in science and medicine is simply because they can become any cell type within the body of a living organism, but are usually derived from adults that are avoiding the controversies associated with embryonic stem cells.

Read more on induced pluripotent stem cells here: brainly.com/question/13235525

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Complete Question:

Induced pluripotent stem cells are cells from adults that have been reprogrammed to imitate embryonic stem cells. Why might induced pluripotent stem cells be a valuable tool in science and medicine?

A. Induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells

B. Induced pluripotent stem cells are the only type of stem cell that's truly pluripotent.

C. Induced pluripotent stem cells may become any cell type in the body, but are fraught with ethical questions over their use.

D. Induced pluripotent stem cells are derived from adult cells and therefore may have DNA abnormalities, allowing scientists to understand the effects of sun exposure or toxins on DNA

4 0

1 year ago

Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8

san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

$\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}$

Firstly, we will factor both denominators

$b^2-64=b^2-8^2=(b-8)(b+8)$

$b^2+7b-8=(b+8)(b-1)$

so, we can plug it back

$\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}$

First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

$LCD=(x-8)(x+8)(x-1)$

3 0

2 years ago

Which is bigger 5.8 or 5.5

frutty [35]

Answer:

5.8 is bigger

Step-by-step explanation:

5 0

2 years ago

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Determine the holes, vertical asymptotes, and horizontal asymptotes of the rational function y=3x^2+10x-8/x^2+7x+12

kompoz [17]

There would be a hole when x = -4.

If you factor both the top and the bottom, you will see that the factor (x + 4) is in both the numerator and denominator. Therefore, the would be a hole when x = -4 because that would also make the denominator 0.

8 0

2 years ago

Find the area of the rectangle with a length of (x^2-2) and a width of (2x^2-x+2)

Katyanochek1 [597]

Area=legnth times width

so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)

so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4

5 0

2 years ago

Read 2 more answers