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kvasek [131]
3 years ago
15

Of all customers purchasing automatic garage door openers, 75% purchase chain-driven model. Let X = the number among the next 15

purchasers who select the chain-driven model. a. What is the frequency function (pmf) of X?
Business
1 answer:
KIM [24]3 years ago
6 0

Answer:

         P(X=x)=C(15,x)\cdot(0.75)^x\cdot(0.25)^{(15-x)}

Explanation:

The <em>probability mass function</em> (<em>PMF</em>), or <em>frequency function</em>, is the function that gives the probabilities that a <em>discrete random variable</em> take some values.

In this problem, it is requested the frequency function (PMF) for the <em>number of purchasers, among the next 15, who select a chain-driven model</em>.

Then , you need to find, the function that gives P(X=0), P(X=1), P(X=2), P(X=3), . . . up to P(X=15).

Such as any function, the frequency  function can be presented as a formula, as a table, or as a graph.

Note that the statement represents a binomial disbribution in which success is that a customer select a chain-driven model and the fail is that a cusotmer does not select a chain-driven model.

The binomial probability for X = the number among the 15 purchasers who select the chain-driven model is given by the formula:

           P(X=x)=C(n,x)\cdot(p)^x\cdot(1-p)^{(n-x)}

Where:

  •  C(n,x)=\dfrac{n!}{x!(n-x)!}
  •   n is the number of times the experiment is performed: 15 in our problem
  • p is the probability of succes: 0.75 in our problem
  • 1-p is the probability of fail: 0.25 in our problem

Then, substitute:

           P(X=x)=C(15,x)\cdot(0.75)^x\cdot(0.25)^{(15-x)}

That is the frequency function.

If you want to give it as a table you must find P(X=1), P(X=2), P(X=3), . . . up to P(X=15) using that function. That is not part of the question.

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nikdorinn [45]

Answer:

The cost of goods sold is $2950

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The specific identification method requires the cost of inventory to be calculated using the actual cost at which the inventory is bought and recorded.

The cost of goods sold will be the cost of tv's that are sold during June. One tv that was sold with serial no 11534894 belonged to the TVs having cost of $1500. The other that was sold belonged to the cost group of $1450 per TV (serial no 11542631).

Thus cost of goods sold will be = 1500 + 1450 = $2950

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MrRa [10]

Sets up a LAN for the office APEX VERIFIED

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Hitman42 [59]

If your team member has worked here much longer than you then the situation can be handled by calling your team attention to the dangers attached to not following the safety rules in a calm and friendly way.

<h3> Who is customer service representative?</h3>

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The rep should handle the situation by pointing their attention to the danger attached to not following the safety rules in a very friendly manner and could also have a superior informed that could help guide them.

Therefore,

If your team member has worked here much longer than you then the situation can be handled by calling your team attention to the dangers attached to not following the safety rules in a calm and friendly way.

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Autopitch devices are made for both​ major- and​ minor-league teams to help them improve their batting averages. When set at the
aivan3 [116]

Answer:

Control limits for x_bar are between 59.076 and 60.924

Control limits for R are between 0.669 and 5.331

Explanation:

Given data:

x_bar = 60 mph

n = 10

R = 3 mph

Step 1: Factors (see table attached)

At n = 10, factors for computing control charts limits are,

A2 = Mean factor = 0.308

D3 = Lower range = 0.223

D4 = Upper range = 1.777

Step 2: Control limits for x_bar

Lower Control limit:

LCL =  x_bar - A2*R = 60 - (0.308)(3) = 60 - 0.924 = 59.076

Upper Control limit:

UCL =  x-bar + A2*R = 60 + (0.308)(3) = 60 + 0.924 = 60.924

The control limits for x_bar are between 59.076 and 60.924

Step 3: Control limits for R

Lower Control limit:

LCL = D3*R = 0.223(3) = 0.669

Upper Control limit:

UCL = D4*R = 1.777(3) = 5.331

The control limits for R are between 0.669 and 5.331

Hope this helps!

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solniwko [45]

Answer:

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Explanation:

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