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maw [93]
3 years ago
5

A math class containing 57 students was divided into two sections one section has three more students than the other how many st

udents were in each section
Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
(3+x)+x=57
3+x+x=57
3+2x=57
2x=57-3
2x=54
x=54/2
x=27
so the first section has 27 students and the second section has 30 students
satela [25.4K]3 years ago
6 0
32 In one section and 25 in section two or vice versa
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A circle passes through (3,-1),(-2, 4), and (6,8)
Vaselesa [24]

Answer:

D = -6, E = -8 , F = 0

Step-by-step explanation:

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

now, when circle passes through (3,-1);

⇒ 3^{2} + (-1)^{2} + D(3) + E(-1) + F = 0

⇒ 3D - E + F + 10 = 0    ...............( equation 1)

when circle passes through (-2,4);

⇒ (-2)^{2} + 4^{2} + D(-2) + E(4)+ F = 0

⇒ -2D + 4E + F + 20 = 0    ...............( equation 2)

when circle passes through (6,8);

⇒ 6^{2} + 8^{2} + D(6) + E(8) + F = 0

⇒ 6D + 8E + F + 100= 0       ................( equation 3)

by solving these 3 equations , we get;

D = -6, E = -8, F = 0

hence,

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

                        = x^{2} + y^{2} - 6x - 8y = 0

5 0
3 years ago
Express 500 g as a percentage of 2.5 kg.​
azamat

Answer:

500 grams is 20 percent of 2.5 kg

Step-by-step explanation:

500*100 = 50,000

50,000/2500=20

8 0
3 years ago
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The amount of time workers spend commuting to their jobs each day in a large metropolitan city has a mean of 70 minutes and a st
Xelga [282]

Answer:

81.85% of the workers spend between 50 and 110 commuting to work

Step-by-step explanation:

We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.

We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

W = \frac{X-μ}{σ} = \frac{X-70}{20}

The values of the cummulative distribution function of the standard normal, which we denote \phi , are tabulated. You can find those values in the attached file.

P(50 < X < 110) = P(\frac{50-70}{20} < \frac{X-70}{20} < \frac{110-70}{20}) = P(-1 < W < 2) = \\\phi(2) - \phi(-1)

Using the symmetry of the Normal density function, we have that \phi(-1) = 1-\phi(1) . Hece,

P(50 < X < 110) = \phi(2) - \phi(-1) = \phi(2) - (1-\phi(1)) = \phi(2) + \phi(1) - 1 =  \\0.9772+0.8413-1 = 0.8185

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.

Download pdf
7 0
3 years ago
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exis [7]

Answer:

-6.47+4.70i.  

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Step-by-step explanation:

100% sure

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Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

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3 years ago
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