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3 years ago

What is round to the nearest ten and hundred

Mathematics

1 answer:

Alina [70]3 years ago

7 0

363 : nearest ten-360
nearest hundred- 400

829 : nearest ten-830
nearest hundred-800

209 : nearest ten-210
nearest hundred-200

663 : nearest ten-660
nearest hundred-700

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I NEED URGENT ASSISTANCE

Nata [24]

Answer:

8 C sometimes

9 64x^8 y^11

10 c 1.28r^2/ t^9

Step-by-step explanation:

Algebraic Operations

Some basic rules must be fresh in our minds when trying to simplify complex algebraic expressions. For example, the power rule respect to the product or quotient:

$\displaystyle \left(\frac{x^n.y^m}{z^p}\right)^q= \frac{x^{qn}.y^{qm}}{z^{qp}}$

$\displaystyle \frac{x^n.x^q}{x^p}= x^{n+q-p}$

$\displaystyle x^{-n}=\frac{1}{x^n}$

Let's face the questions at hand

8. A number is raised to a negative exponent is negative?

Following the expressions recalled above, let's pick the expression

$\displaystyle 3^{-2}=\frac{1}{3^2}=\frac{1}{9}$

This is a negative power resulting in a positive number

Now we pick

$\displaystyle (-2)^{-3}=\frac{1}{(-2)^3}=-\frac{1}{8}$

This time, the negative power leads to a negative result, so it doesn't matter the sign of exponent to determine the sign of the result

Answer: C sometimes

9 simplify(4xy^2)^3(xy)^5

$(4xy^2)^3(xy)^5=4^3x^3(y^2)^3x^5y^5$

$=64x^3y^6x^5y^5$

$=64x^8y^{11}$

10 simplify(2t^-3)^3(0.4r)^2

$(2t^{-3})^3(0.4r)^2=2^3(t^{-3})^30.4^2r^2$

$=8t^{-9} 0.16 r^2$

$=1.28t^{-9} r^2$

$\displaystyle \frac{1.28 r^2}{t^9}$

7 0

3 years ago

An 11-inch string is cut into 3 equal pieces. which expression shows the length of each piece?

vaieri [72.5K]

11 divided by 3 equals 3.66 repeating

5 0

3 years ago

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Question:

allochka39001 [22]

Answer:

It is A

Step-by-step explanation:

I cant explain step by step I am in a rush but it is A

3 0

3 years ago

Please Help Will mark Brainliest

ankoles [38]

The answer is “a”.

explanation:
the dot is open and the arrow is pointed to the left.

5 0

2 years ago

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The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

liq [111]

Answer:

Option B. 59%

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

$A(t)=136(1.123)^{4t}$

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

$rate=(1.123)^{4t}=(1.123)^4=1.590$

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

8 0

4 years ago