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4vir4ik [10]
3 years ago
10

In a class of 28 students, 12 earned an A on the final exam, 6 earned a B, 4 earned a C, and the remaining students failed. Base

d on these results, what is the experimental probability that a student will not earn an A or a B?
Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

  5/14 ≈ 35.7%

Step-by-step explanation:

(12 +6) = 18 of the 28 students earned an A or a B. So, the experimental probability that a student did not earn that grade is ...

  p(<B) = (28 -18)/28 = 10/28

  p(<B) = 5/14 ≈ 35.7%

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tia_tia [17]
Answer: 2.663043987
explanation: use calculator
7 0
2 years ago
What is 6(5−8v)+12=−54
zlopas [31]

Answer: v = 2

Step-by-step explanation:

30-48v+12 = -54

-48v = -54-30-12

\frac{-48v}{-48} = \frac{-96}{-48}

v = 2

7 0
3 years ago
Read 2 more answers
On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)
aleksandr82 [10.1K]

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = (\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})

OP.Cosθ = 1×Cosθ = \frac{1}{\sqrt{2}}

Cosθ = \frac{1}{\sqrt{2}}

θ = \frac{\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integers

Similarly, OP×Sinθ = 1×Sinθ = -\frac{1}{\sqrt{2}}

Sinθ = -\frac{1}{\sqrt{2} }

θ = \frac{5\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integer

Common value of θ will be, θ = \frac{7\pi }{4}

Option B will be the answer.

5 0
3 years ago
Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
2 years ago
The demand for video recorders has been estimated to be Qv = 134 − 1.07Pf + 46Pm − 2.1Pv − 5I, where Qv is the quantity of video
stepladder [879]

Answer:

The Video recorders are inferior goods.

Step-by-step explanation:

As Q_{v} =134-1.07Pf+46Pm-2.1Pv-5I

where;

The price of the recorders films are increasing by a term 1.07 which gives that the Price is increasing by a little. Also adding the Price of video recorder is increasing by a factor 2.1 and the Revenue or income is increasing by a term 5 (Which is high) so, revenue and price are increasing leaving the quality of the voice recorder decreasing by a large margin for maintaining the balance.

As

                               Revenue =price*Quality

So, in conclusion the quality decreases and thus the video recorders are inferior goods.

5 0
3 years ago
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