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mars1129 [50]
3 years ago
12

Kyle is using 4 pounds of peaches to make pies. How many ounces of peaches is Kyle using for the pies? (1 pound = 16 ounces)

Mathematics
2 answers:
Anastasy [175]3 years ago
7 0
64 ounces. 4*16=64....
professor190 [17]3 years ago
4 0
Should it be 64 cause that what i got<span />
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In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
3 years ago
Please help I am stuck. Would you also please explain on how to solve?
Bezzdna [24]

Answer:

<D is correct its confusing on the solving but

Step-by-step explanation:

4 0
3 years ago
You have 480 grams of a radioactive kind of samarium. If its half-life is 90 years,
lisov135 [29]

Answer:

120 grams will be left after 180 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                             N(t)=N_0(\frac{1}{2})^\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know that:

  • The initial quantity is 480 g,
  • The half-life is 90 years,
  • 180 years is the time elapsed.

And we want to find how much will be left. For this we use the above formula.

N(t)=480\left(\frac{1}{2}\right)^{\frac{180}{90}}\\\\N(t)=480\left(\frac{1}{2}\right)^2\\\\N(t)=480\cdot \frac{1}{2^2}=120

120 grams will be left after 180 years.

3 0
3 years ago
Please help as soon as possible.
aniked [119]

Answer:

C = 37.6991

Step-by-step explanation:

The equation for the circumference of a circle is given: C = π · d

where, d is the diameter of the circle.

Plug in the value of d = 12 and use the π button on the calculator.

C = π · 12

C = 37.6991

5 0
3 years ago
Read 2 more answers
A 13.5-meter ladder leans against a brick wall and the ladder makes a 75∘ with the wall. The distance d the ladder goes up the w
Alex73 [517]

Answer:

3.5 m

Step-by-step explanation:

Use Pythagorean theorem to find the distance (d) the distance goes up the wall = adjacent to the angle 75° that is formed with the wall.

Length of ladder = the hypothenuse = 13.5 m

Thus, we would use:

Cos75 = adjacent/hypothenuse

Cos 75 = d/13.5

Multiply both sides by 13.5

13.5*cos(75) = d

13.5*0.2588 = d

3.4938 = d

d ≈ 3.5 m (nearest tenth)

3 0
3 years ago
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