1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
It's just telling you to multiple like 9×1=9 9×2=18 and so on.
AG and GB must be congruent and CG and GD must be congruent as well
Answer:
12.94
Step-by-step explanation:
By the law of sines:
x / sin(35) = 7.9 / sin70
x = 7.9 * sin(70)/sin(35)
= 7.9 * 0.9397 / 0.5736
= 12.94
Answer:
I can’t just tell you the answer cause that’s all your looking for let me know what u need help with
Step-by-step explanation:
