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3 years ago

Please help I am stuck. Would you also please explain on how to solve?

Mathematics

1 answer:

Bezzdna [24]3 years ago

4 0

Answer:

<D is correct its confusing on the solving but

Step-by-step explanation:

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How to integrate cos^-2x . Question from Alevel Pure Maths 3

VashaNatasha [74]

Answer:

I do think I can answer this

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3 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

3 years ago

Find the inverse of y=100-x^2

AnnyKZ [126]

Answer:

The inverse is ±sqrt(100-x)

Step-by-step explanation:

To find the inverse, exchange x and y

x = 100 -y^2

Solve for y

Subtract 100 from each side

x - 100 = -y^2

Divide by -1

-x +100 = y^2

Take the square root of each side

±sqrt(100-x) = sqrt(y^2)

±sqrt(100-x) =y

The inverse is ±sqrt(100-x)

5 0

3 years ago

Please help i am timed

Svetlanka [38]

7a^3(6a^2 + a)^2 - 4a^6

All we have to do here is basically add and subtract exponents!

(6a^2 + a)^2 = 36a^4 + a^2

7a^3(36a^4 + a^2) - 4a^6

252a^7 + 7a^5 - 4a^6

Answer is C.

5 0

3 years ago

If the length of side ab is 17, is triangle abc a right triangle?

bagirrra123 [75]

It can be both.
as there is no length of height or hypotenuse...

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3 years ago